Ask question

Ask question

All categories

aleksandr82 [10.1K]

3 years ago

12

So If Mr. Cohen drives 84 2/10 miles on Tuesday,84 6/10 miles on Wednesday,85 miles on Thursday how many miles would He drive on

Sunday

2 answers:

ziro4ka [17]3 years ago

7 0

I think that he would drive 86 7/10 miles because it goes up by 4/10 miles each day

alexira [117]3 years ago

7 0

Because the miles Mr. Cohen drives increase by $\frac{2}{5}$ on each day, so Mr. Cohen will drive $85 + \frac{2}{5}$ × 3 = 86 $\frac{1}{5}$ on Sunday

You might be interested in

Mariah and isaiah each deposited $7000 into accounts that earn 6% interest the graph shows the amount of interest each account e

STALIN [3.7K]

Answer:

its Isaiah he's the most financially stable

8 0

2 years ago

Read 2 more answers

Solve the system of equations.

MAXImum [283]

Answer:

D. (-2, -6) and (5,15)

Step-by-step explanation:

When you set the equations together, you get x^2-3x-10. You then set this equation equal to zero and get (x-5)(x+2) or x=-2 and x=5. Then, plug these x-values into each equation to get your y-values.

8 0

2 years ago

Justine is planting flowers in a line that is 1/2 of a yard long. She is going to plant 6 flowers. How far apart will each flowe

erica [24]

Answer:

3 inches apart

Step-by-step explanation:

1/2 yard is 1ft. 6in. in decimal that is 1.5 ft

1.5 ÷6 = 0.25ft

0.25ft is 3 inches so the answer is three inches apart

6 0

3 years ago

find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P

Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, $(t,y(t))=(t,t^2-2t-5)$ , where $t>2$ . The slope of the secant line through P and Q is given by the difference quotient,

$\dfrac{(t^2-2t-5)-(-5)}{t-2}=\dfrac{t^2-2t}{t-2}=\dfrac{t(t-2)}{t-2}=t$

where we are allowed to simplify because $t\neq2$ .

Then the equation of the secant line is

$y-(-5)=t(x-2)\implies y=t(x-2)-5$

Taking the limit as $t\to2$ , we have

$\displaystyle\lim_{t\to2}t(x-2)-5=2(x-2)-5=2x-9$

so the slope of the line tangent to the curve at P as slope 2.

- - -

We can verify this with differentiation. Taking the derivative, we get

$\dfrac{\mathrm dy}{\mathrm dx}=2x-2$

and at $x=2$ , we get a slope of $2(2)-2=2$ , as expected.

4 0

3 years ago

Sole the equation problem

atroni [7]

The answer is 100!!!

6 0

2 years ago

Read 2 more answers