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3 years ago

If a space of 18 inches is allowed for each person, how many persons can be seated in a row of bleacher seats 90 feet long?

Mathematics

1 answer:

scoray [572]3 years ago

3 0

ONE FOOT IS = TO 12INS SO 90*12=1080
1080/18=60
SO THE ANSWER IS THE BLEACHERS CAN SEAT 60 POEPLE

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Horace take a taxi uptown and the fare is $12.78 he wants to give the taxi a 10% tip if Horace gives the driver a $20 bill how m

Olegator [25]

Answer:

$5.94

Step-by-step e

12.78 + 10% (1.28) = 14.06

20.00 - 14.06 = 5.94

7 0

3 years ago

8 x 4 = ( y x 7 ) - ( y x 3 )<br><br> What is y?

ASHA 777 [7]

8x4=32
32=(yx7)-(yx3)
(yx7)=7y
(yx3)=3y
32=7y-3y
7y and 3y are like terms so you subtract them
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32=4y
then divided 4y by 4 (to get y on its own) this cancels out if you ÷ 4y on one side of the equation you have to divide on the other side to make it balanced 32÷4=8
y=8

4 0

3 years ago

ANSWER ASAP PLEASE<br> look at the photo

Liula [17]

Step-by-step explanation:

Area of trapezium = 1/2(a+b)h

= 1/2(10+24)12

= 1/2×34×12

= 204 square units

3 0

3 years ago

A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When

Tanya [424]

Answer:

$ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434$

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

$\hat p = \frac{24}{250}= 0.096$

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And the margin of error would be:

$ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434$

4 0

3 years ago

Complete the point-slope equation of the line through ( 1, 10) and (5.2).

forsale [732]

Answer:

y = -2x + 12

Step-by-step explanation:

The point-slope equation for a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept(value of y when x = 0).

(1,10)

This means that when x = 1, y = 10. So

10 = m + b

(5,2)

This means that when x = 5, y = 2. So

2 = 5m + b

From the first equation, b = 10 - m. So

2 = 5m + 10 - m

2 = 4m + 10

4m = -8

m = -2

And

b = 10 - m = 10 - (-2) = 10 + 2 = 12

y = -2x + 12

3 0

3 years ago