<span>Instead of thinking about reliability think of failure. 99.999% reliability =0.00001 chance of failure. And 95% reliability =0.05 chance of failure. Assuming failures are independent (they probably are not) the chance of n servers failing is (0.05)n Find n such that (0.05)n=(0.00001) now do it for (0.14)n=(0.00001)</span>
Answer:
Sorry
Step-by-step explanation:
I don't know the answer
The answer would be the first one :)
We have the following expression given:

We can start selecting as common factor 4y^2 and we got:

Now we can select y+7 as common factor and we got:

So then our final answer would be: