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scoray [572]
3 years ago
12

Write the equation in slope-intercept form of the line parallel and line perpendicular to the given line.

Mathematics
1 answer:
nordsb [41]3 years ago
6 0
I don’t know if this is right but for
Y=4x+7 your m would be 4/1 and where you begin would be 7
2x-5y=10: you would take 10 and divide it by the two numbers in front (10 divided by 2= 5) (10 divided by -5=-2)
For 3x+4y=16 you would do the same you did for the last equation (16 divided by 3= 5.3) (16 divided by 4=4
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Hi,so I've tried solving this problem for a while and I just don't get it,if you could give me some ideas I would appreciate it.
ziro4ka [17]

Answer:

187 cm²

Step-by-step explanation:

The bottom rectangle area is easy, it is 15*9 = 135 cm².

To find the area of the triangle, you only need the base width and its height (you don't need the hypotenuse). You can then use the formula: area triangle is base times half height.

The base width is 15-7 = 8 cm

The height is 22-9 = 13 cm

So the area of the triangle is 13*8/2 = 52 cm²

Together with the 135 of the rectangle that sums to 52+135 = 187 cm².

4 0
3 years ago
PLEASEEEEEE HELPPPP!!!!
pogonyaev
I believe this would be correct.

6 0
3 years ago
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Sal and her three friends plan to bowl one or two games each. Each game costs $2.50 each. Identify the independent and dependent
tino4ka555 [31]
So the dependent is the number of games because it's not definite they dont know for sure. so the domain always involves money!!! always! the range wiyld be the numbers they migh play like 8-10 so 4 to 8 is the range value. so determining off of that the indepedent variable would be the total cost becuase it wont change so your answer is C hope this helped have a good day!!!
3 0
3 years ago
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Bishon needs to sell at least 0.3 of his collection of sports cards to
diamong [38]

Answer:

no because 3/20 is eguivilent to 0.15 whitch is half of 0.3

3 0
3 years ago
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(-36)^1/2=<br> a.) 1/6<br> b.) -6<br> c.) no real number
hjlf

It's suppose to be -18 so I guess no real number....

4 0
3 years ago
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