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Lady_Fox [76]
3 years ago
9

Solve for x and graph​

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0
X is greater than or equal to 1

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Alja [10]

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So

? = 8 x 7 = 56

Answer

Missing side length = 56

7 0
3 years ago
Raheem bought 3 pounds of bananas about how many kilograms did he buy??
ehidna [41]
1 pound ≈  0.4536 kg.

3 pounds ≈  3 * 0.4536 ≈ 1.3608 kg

Hence 3 pounds ≈ 1.3608 kg.
6 0
3 years ago
I need to find the answer to these questions in about 10 minutes or I'm screwed. please help me out.
Savatey [412]
For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.

For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.

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7 0
3 years ago
Given that 3x+2y=5a+b and 4x-3y=a+7b, solve for y-x in terms of a and b.​
Eduardwww [97]

Answer:

y - x = - 2 b

Step-by-step explanation:

Given-

3 x + 2 y = 5 a + b...................(i)

4 x - 3 y = a + 7 b.....................(ii)

<em><u>Multiply by 3 and 2 in equation (i) & (ii) respectively-</u></em>

<em><u>Add equation (iii) &  (iv)-</u></em>

9 x + 6 y = 15 a + 3 a...................(iii)

<u>8 x - 6 y = 2 a + 14 b</u> ...................(iv)

17 x = 17 a + 17 b

<u>x = a + b</u>

Put x = a + b in equation (i)-

<em>2 y = 5 a + b - 3 a - 3 b</em>

<em>2 y = 2 a - 2 b</em>

<u>y = a - b </u>

<em>∴ y - x = a - b - ( a + b )</em>

<em>y - x = a - b - a - b</em>

y - x = - 2 b

3 0
3 years ago
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

P(0) =\frac{1200}{1+11}

P(0) =\frac{1200}{12}

P(0) = 100

Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

t = 30

P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

Solving (c): \lim_{t \to \infty} P(t)

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

P(\infty) = \frac{1200}{1 + 11 * 0}

P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

5 0
3 years ago
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