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Ad libitum [116K]
3 years ago
6

A standard six-sided die is rolled 6 times. You are told that among the rolls, there was one 1, two 2's, and three 3's. How many

possible sequences of rolls could there have been? (For example, 3,2,3,1,3,2 is one possible sequence.)
I tried this and I still don't get it. PLEASE HELP
Mathematics
2 answers:
S_A_V [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Exactly two numbers appear:

There are  

(

6

2

)

(62)

ways for two of the six numbers to appear. On each of the six rolls of the die, there are two possible outcomes, giving  

(

6

2

)⋅

2

6

(62)⋅26

possible outcomes in which two of the six numbers appear. However, of these  

2

6

26

sequences, there are two in which the same number is rolled six times. Thus, the probability of exactly two numbers appearing in six rolls of the die is  

(

6

2

)⋅(

2

6

−2)

6

6

MArishka [77]3 years ago
6 0

Answer:

34

Step-by-step explanation:

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HELP me on this please
Rzqust [24]

Answer:

angle FEA is 100°

angle AEC is 20°

angle CEG is 60°

Step-by-step explanation:

angle AEC=angle DEB=20°

angle AEG=angle FED=80°

80°-20°=60°; angle CEG=60°

angle FEA+angle AEC+ angle CEG=180°

angle FEA=100°

6 0
3 years ago
I will give brainlest please explain and answer
OLga [1]

Answer: the answer is D.

Step-by-step explanation:

8 0
3 years ago
Please help me asap!!
andreev551 [17]

Answer:

I believe it's 36

Step-by-step explanation:

Also is this a test lol?

7 0
3 years ago
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What is the equivalent fraction for 3,2,6,4 whole number?
maw [93]
3/1, 2/, 6/, 4/1, hope I helped!
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