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ella [17]
3 years ago
6

At 9:00 am, a dog chased a squirrel 8 miles north. The dog gave up and stopped chasing the squirrel at 10:00 am. What was the av

erage velocity of the dog while he was chasing the squirrel?
8 mph south

16 mph north
Chemistry
1 answer:
Leto [7]3 years ago
5 0

8mph North

Explanation:

Given parameters:

Start time = 9.00am

Final time = 10.00am

Displacement = 8miles north

Unknown:

Average velocity of the dog = ?

Solution:

Velocity is the change of displacement with time. It is expressed as:

           Velocity = \frac{Displacement}{Time}

The change in time from 9 - 10am is 1 hour:

       Velocity =  \frac{8}{} = 8mph

The velocity has both magnitude and direction and it is better written as 8mph due north.

Learn more:

Velocity brainly.com/question/2562700

#learnwithBrainly

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