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AleksandrR [38]
3 years ago
13

Write the symbol for nitrogen which has 9 neutronsHow do I solve this?

Chemistry
1 answer:
diamong [38]3 years ago
7 0
If you mean lewis dot symbol you need a nuclide you get the number of proton (z) its equal to electrons since the atom is nutral then you make the elctron configuraion after that you take the number of electrons on the outer energy level( ex:k²L² in this case its the 2 on the L)and if you have 7 electrons and the atom is nitrogen so it becomes
_
:N:
.
Hope that helped
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Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L  N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

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