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larisa86 [58]
3 years ago
9

A particular solvent with ΔS∘vap=112.9J/(K⋅mol) and ΔH∘vap=38.0kJ/mol is being considered for an experiment. In the experiment,

which is to be run at 75 ∘C, the solvent must not boil. Based on the overall entropy change associated with the vaporization reaction, would this solvent be suitable and why or why not? View Available Hint(s)
Chemistry
1 answer:
Dovator [93]3 years ago
4 0

Answer:

The solvent will be not be suitable because ΔS > 0

Explanation:

The entropy measures the disorder of the system, and by the second law of the thermodynamics, it's always increasing. So, a glass that broked (increased in disorder) does not intend to be fixed naturally.

So, when ΔS > 0, it means that the disorder in the system increased, the reaction occurred spontaneously. ΔSºvap is positive for that solvent, so it means that it will boil.

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Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base
Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

\frac{r_{cation}}{r_{anion}}

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation, Na^+ = 102 pm

Radius of cation, Br^- = 196 pm

\frac{r_{cation}}{r_{anion}}=\frac{102}{196}=0.520

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.

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3 years ago
What two statements makes primary and secondary succession similar? 10 points
Dvinal [7]

Explanation:

I want to say either a or b because primary is based on the habitat and whatever happens after while secondary is the result to disturbance causing an effect

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3 years ago
A compound that conducts electricity when dissolved in water would most likely be classified as
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Answer:

Electrolyte

Explanation:

A compound that conducts electricity when dissolved in water would most likely be classified as electrolyte.

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The ionic compounds are called electrolyte and electrolyte solution is formed when they dissolve in water.

For example when sodium chloride is placed into water it split into ions and conduct electricity because of mobile ions.

Chemical equation:

NaCl → Na⁺ + Cl⁻

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Explanation:

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