Triangle Abc has vertices A(-2,5),B(1,0),andC(6,-2).what are the coordinates of the vertices of A’B’C for Ry-axis?
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Answer:
Step-by-step explanation:
Given:
The above triangle
Required
Solve for AB in terms of a, b and angle C
Considering right angled triangle BOC where O is the point between b-x and x
From BOC, we have that:
Make h the subject:
Also, in BOC (Using Pythagoras)
Make the subject
Substitute for h
becomes
Factorize
In trigonometry:
So, we have that:
Take square roots of both sides
In triangle BOA, applying Pythagoras theorem, we have that:
Open bracket
Substitute and
in
Open Bracket
Reorder
Factorize:
In trigonometry:
So, we have that:
Take square roots of both sides
I hope this helps you
Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,