A cone has a base that is a shape of a circle. The length across is 16 feet. The height is 8 feet and the slant height is 10 fee
1 answer:
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Answer:
Answers are in bold type
Step-by-step explanation:
f(x) =
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.
The range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57 and increases when 57 > x > ∞
The x - intercepts: = 0
x(x - 114x) = 0
x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept. So, 0^2 - 114(0) = 0
y-intercept is (0, 0)
Answer:
w= -9/8
Step-by-step explanation:
-1/3w -3/5 = 1/5w
+1/3w +1/3 w
-3/5=1/5w+1/3w
Make common denominators to combine like terms of the right
-3/5=1/5w+1/3w
*3 *5
-3/5=3/15w+5/15w
-3/5=8/15w
multiply both sides by the reciprocal of 8/15 which is 15/8
-3/5*15/8=8/15w*15/8
*
----> cross reduce 5 in the denominator becomes 1 and 15 in the numerator becomes 3
*
-----> now multiply across
w= -9/8