A candle burns down at the rate of 0.5 inches per hour. The original height of the candle was 9 inches.

2 answers:

3 0

The ordered pairs would be,

(1, 8.5)
(2, 8)
(3, 7.5)
(4,7)
(5, 6.5)
(6, 6)

I got the ordered pairs from the question since it stated that the length of the candle decreased .5 every hour. I just corresponded the hour to the length of the candle.

I hope this helped!

Brainliest answer is always appreciated!

olga_2 [115]3 years ago

3 0

Answer:

dont report me i just want Mr. Kaikerscupcake to get brainliest

Step-by-step explanation:

because you need 2 people to be able to give some one brainliest:)

You might be interested in

Show or describe two different ways to complete the comparison using < , > ,or =: 0.26 () 0.4

nordsb [41]

0.26 < 0.4
Reason: 0.26 is less than 0.4 which also can be written as 0.40.
The "mouth" points to the bigger number.

7 0

3 years ago

A kite is flying 70 feet above the ground and is attached to a string tied to a stake on the ground. The angle of elevation form

frozen [14]

If you draw a diagram of this, your given values of the resulting triangle give you the sides opposite and adjacent of the angle. The formula that uses these sides is tangent.

The tangent of an angle is equal to the ratio of the opposite side over the other non-hypotenuse side (adjacent).

Therefore;

$tan(40)=70/x$
$0.83909963117=70/x$
$0.83909963117x=70$
$x=70/0.83909963117$
$x=83.4227514823$

Where x is the length of the string in feet.

3 0

3 years ago

A researcher is interested in estimating the difference in two population proportions. A sample of 400 from each population resu

sergey [27]

Answer: (-0.086, 0.026)

Step-by-step explanation:

The confidence interval for the difference of two population proportion is given by :-

$p_1-p_2\pm\ z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}$

Given : Significance level : $\alpha: 1-0.90=0.10$

Critical value : $z_{\alpha/2}=1.645$

Sample size : $n_1=400,\ n_2=400$

$p_1=0.61,\ p_2=0.64$

The 90% confidence interval for the difference in the population proportions will be :-

$0.61-0.64\pm\ (1.645)\sqrt{\dfrac{0.61(1-0.61)}{400}+\dfrac{0.64(1-0.64)}{400}}\\\\\approx-0.03\pm0.056=(-0.03-0.056,-0.03+0.056)\\\\=(-0.086, 0.026)$