Ask question

Ask question

All categories

2 years ago

12

A kite is flying 70 feet above the ground and is attached to a string tied to a stake on the ground. The angle of elevation form

ed by the string and the ground is 40°. Find the length of the string to the nearest foot.

2 answers:

Ganezh [65]2 years ago

4 0

Answer:

94 feet.

Step-by-step explanation:

The angle of elevation is the angle made by the eye of the observer and the ground level. In this instance, it is the angle formed by the string and the ground which is 40°.

From the attached diagram, the length of the string is x and the height above the ground is 70 feet. These two sides are the hypotenuse and the opposite sides respectively

Using SOH CAH TOA

Sin 40 = 70/x

x = 70/sin 40

x = 93.95 feet.

The length of the string to the nearest foot is 94 feet.

rosijanka [135]2 years ago

3 0

Taking the length of the string to be the hypothenuse and the vertical height above the ground to be the 'opposite' side,
the length of the string
= 70/sin(40°)
= 109 feet

You might be interested in

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0

3 years ago

The ages of undergraduate students in a state

Elan Coil [88]

The percent of students that are aged 19 years or more is determined as 84%.

<h3>One standard deviation below the mean</h3>

In a normal distribution curve 1 standard deviation below the mean is defined as follows;

1 std below mean : M - d = 16%

M - d = 20.6 yrs - 1.3 yrs = 19.3 years ≈ 19 years

19 years or more will occur at (M - d) + (M) + (M + 2d) = 100% - (M - d)

= 100% - 16%

= 84%

Thus, the percent of students that are aged 19 years or more is determined as 84%.

Learn more about normal distribution here: brainly.com/question/4079902

#SPJ1

7 0

2 years ago

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

7 0

2 years ago

(4x^(2)-7x+11)/(5x^(2)-3x+2)

Semmy [17]

Answer:

(4x^(2)-7x+11)/(5x^(2)-3x+2)

Step-by-step explanation:

6 0

3 years ago

Daniela y Jorge can en bicicleta y salen del mismo lugar, Daniela avanza 6km y luego retrocede 2km mientras que Jorge avanza 8km

den301095 [7]

Answer:

a) 1 km

b) Amaya

c) Jorge

HOPE THIS HELPS ;P

7 0

2 years ago