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Anvisha [2.4K]
3 years ago
14

Draw diagram to rerpresent the mixed number 3 2/3. How can u write this as a single fraction greater than one

Mathematics
2 answers:
muminat3 years ago
8 0
11/3 draw whatever u want
Alina [70]3 years ago
6 0
U can say 11/3 because i know that way works 

hope this helps:)

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The area of a rectangular garden is 3927cm . If the width of the garden is 51 m , what is its length?
Galina-37 [17]

Answer:

77

Step-by-step explanation:

The area of a rectangle is A = lw. 'A', the area, is 3927, and 'w', the width, is 51. By substituting the values in, we get that 3927 = 51L. Dividing both sides by 51, we get that L, the length, is 77.

6 0
3 years ago
the graph of the function f(x) = ax^2 + bx + c (where a, b, and c are real and non zero) has two x- intercepts. explain how to f
Dovator [93]
The vertex of the parabola is given by :

                          \displaystyle{ ( \frac{-b}{2a}, f(\frac{-b}{2a}) ).

So, \displaystyle{ \frac{-b}{2a} is the first coordinate of the vertex, which means it is also the point where the line of symmetry passes.

The line of symmetry divides the parabola into 2 symmetrical parts: the x-intercepts are also symmetrical to each other with respect to this line.


So, if one of the x-intercepts is \displaystyle{ (\frac{-b}{2a}+3, 0), that is 3 units to the right of the x-intercept, the other must be 3 units to the left. Thus, the second x-intercept is :

Answer: \displaystyle{ (\frac{-b}{2a}-3, 0),
4 0
4 years ago
Write <br> 17/25 as a decimal.<br> A) 0.068 <br> B) 0.68 <br> C) 1.471 <br> D) 6.8
ikadub [295]
I think it is D) 6.8
3 0
4 years ago
Read 2 more answers
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
4 years ago
How do you do this question?
lukranit [14]

Answer:

0.001591

Step-by-step explanation:

The power series for arctan(x) is:

arctan(x) = ∑ (-1)ⁿ x²ⁿ⁺¹ / (2n + 1)

Substituting 5x:

arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺¹ / (2n + 1)

Multiply both sides by x:

x arctan(5x) = ∑ (-1)ⁿ x (5x)²ⁿ⁺¹ / (2n + 1)

Simplify:

x arctan(5x) = ∑ (-1)ⁿ (5x) (5x)²ⁿ⁺¹ / (10n + 5)

x arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺² / (10n + 5)

Multiply top and bottom by 5:

x arctan(5x) = ∑ (-1)ⁿ 5 (5x)²ⁿ⁺² / (50n + 25)

Integrate:

∫ x arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺³ / ((50n + 25) (2n + 3))

Evaluate between x = 0.1 and x = 0:

∫₀⁰¹ x arctan(5x) = [∑ (-1)ⁿ (5x)²ⁿ⁺³ / ((50n + 25) (2n + 3))] |₀⁰¹

∫₀⁰¹ x arctan(5x) = ∑ (-1)ⁿ (0.5)²ⁿ⁺³ / ((50n + 25) (2n + 3))

This is an alternating series.  We can approximate it with Alternating Series Estimation.

bₙ₊₁ ≥ ε

(0.5)²⁽ⁿ⁺¹⁾⁺³ / ((50(n+1) + 25) (2(n+1) + 3)) ≥ 0.000001

(0.5)²ⁿ⁺⁵ / ((50n + 75) (2n + 5)) ≥ 0.000001

n ≥ 3

So the approximation is the sum of the terms from n=0 to n=3.

(-1)⁰ (0.5)²⁽⁰⁾⁺³ / ((50(0) + 25) (2(0) + 3))

+ (-1)¹ (0.5)²⁽¹⁾⁺³ / ((50(1) + 25) (2(1) + 3))

+ (-1)² (0.5)²⁽²⁾⁺³ / ((50(2) + 25) (2(2) + 3))

+ (-1)³ (0.5)²⁽³⁾⁺³ / ((50(3) + 25) (2(3) + 3))

= 0.0016667 − 0.0000833 + 0.0000089 − 0.0000012

= 0.001591

7 0
3 years ago
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