The graph below represents a rock climbers height as she acends a hill. Part A- The above graph is (circle one) linear/ nonlinea
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The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Given the coordinate (15, -21) and the line 5x + 2y = 4
In order to get the point on the line 5x + 2y =4, we can a point on the line
Let x = 0
5(0) + 2y = 4
2y = 4
y = 2
The point (0, 2) is on the line.
Find the distance between the point (15, -21) and (0, 2) using the distance formula
Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Learn more here: brainly.com/question/22624745
Answer:
The solutions are -3 and -6
Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18
Now, to get the roots, we would use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)
The solutions are -3 and -6
Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18
Now, to get the roots, we would use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)