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3 years ago

14

a submarine travel 184.4 meters below the water's surface. It took 23 1/2 minutes maintain a speed during a recent how far did y

ou send in one minute

1 answer:

cupoosta [38]3 years ago

6 0

If the submarine descended 184.4 meters in 23.5 minutes, its rate of descent was ...

... (184.4 m)/(23.5 min) ≈ 7.847 m/min

The submarine descended about 7.85 meters in one minute.

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The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 x, squared, plus, left

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Center = $(h,k) = (0,2.25)$
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<u>Step-by-step explanation:</u>

Here we have following equation : $x^{2}+(y-2.25)^{2} = \dfrac{196}{169}$

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ $(x-h)^2+(y-k)^2=r^2$ ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒ $x^{2}+(y-2.25)^{2} = \frac{196}{169}$

⇒ $(x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2$

On comparing this equation with equation (1) we get :

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

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