The given inequality is
First we need to remove the absolute sign , and when we do so , we will get a compound inequality, that is
To solve for x, first we need to get rid of 10. and for that, we have to do subtraction
Now we need to get rid of 9, and for that, we do division
So the required solution is
Answer:
x = 7
y = 12
Step-by-step explanation:
To do this question you have to know your exponent rules, but also you need to know how to add fractions.
To multiply
6^(1/3) × 6^(1/4)
you can keep the 6 and just add the exponents.
That's why the answer is set up on the form 6^(x/y)
To add fractions, you need a common denominator, it is 12.
1/3 is 4/12.
1/4 is 3/12.
So 1/3 + 1/4
is the same as:
4/12 + 3/12
= 7/12
7/12 is the exponent you are looking for.
x = 7 and y = 12.
6^(1/3) × 6^(1/4)
=6^(7/12)
Answer:
all real numbers except ±5.
Step-by-step explanation:
Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.
The domain of (f/g)(x) is all real numbers except ±5.
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Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:
- add 25 and take the square root: x^2=25; x=±√25.
- factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
Answer:
12 pull
As 48 seconds + 20 seconds push = 68 seconds
Step-by-step explanation:
Because she did 10 push = 20 seconds = 2 seconds each
12 pull = 48 seconds = 4 seconds each
= 68 seconds combined.
Workings;
18 seconds found for the first set
We then find a divider of 68 and know that
6 x 3 = 18 seconds push
12 x 3 =36 seconds pull T= 54
14 left over = 1 x 12 seconds pull
+ 2 seconds push
= 10 push = 20 seconds combined.
= 12 pull = 48 seconds combined.
Answer:
Step-by-step explanation:
Given
Let
Undergraduates
Graduates
So, we have:
-- Total students
--- students to select
Required
From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.
First, we calculate the total possible selection (using combination)
So, we have:
Using a calculator, we have:
The number of ways of selecting 2 from 3 undergraduates is:
The number of ways of selecting 2 from 5 graduates is:
So, the probability is:
