The pic is kinda blurry so I can’t read it
Answer:

Step-by-step explanation:
Given:
To find:
- Summation notation of the given series
Summation Notation:

Where n is the number of terms and
is general term.
First, determine what kind of series it is, there are two main series that everyone should know:
A series that has common difference.
A series that has common ratio.
If you notice and keep subtracting the next term with previous term:
Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.
Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:
<u>Arithmetic Sequence</u>

Where
is the nth term,
is the first term and
is the common difference:
So for our general term:

And for number of terms, substitute
= 251 and solve for n:

Now we can convert the series to summation notation as given the formula above, substitute as we get:

Both A and C would be solutions to the equation.
In order to solve for this you must first get the equation equal to 0.
2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)
Now we can plug these values into the quadratic equation.





or -1/2 for the first answer

or -2 for the second answer
This is a horizontal line passing through the point (0,-1).
Slope = zero.
Answer:
I think i would be c or a but im not sure
step-by-step explanation: