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1 year ago

I don’t know what to do

Mathematics

1 answer:

n200080 [17]1 year ago

4 0

Answer:

x = 7

y = 12

Step-by-step explanation:

To do this question you have to know your exponent rules, but also you need to know how to add fractions.

To multiply

6^(1/3) × 6^(1/4)

you can keep the 6 and just add the exponents.

That's why the answer is set up on the form 6^(x/y)

To add fractions, you need a common denominator, it is 12.

1/3 is 4/12.

1/4 is 3/12.

So 1/3 + 1/4

is the same as:

4/12 + 3/12

= 7/12

7/12 is the exponent you are looking for.

x = 7 and y = 12.

6^(1/3) × 6^(1/4)

=6^(7/12)

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What would the new point be If you rotated the point (3,-5) 270 clockwise.

timurjin [86]

Answer:

see below

Step-by-step explanation:

When you rotate a point 270 degrees clockwise (x, -y) becomes (-y, -x) so the answer would be (-5, -3).

5 0

3 years ago

Find an equation to the line perpendicular to 4x + 36y =80 an goes through the point (3,6) write answer in form y= Mx+b

Veronika [31]

Answer:

$\textbf{y = 9x + 21 }\\$

Step-by-step explanation:

$\textup{Given equation is: $4x + 36y = 80 $}\\\textup{This can be written in the form of $y = mx + a$ as follows}\\$ 36y = -4x + 80 $\\$ \implies y = \frac{80}{36} - \frac{4}{36}x $\\$ \implies y = \frac{-1}{9}x + \frac{20}{9} $\\\textup{This means that the slope of this line is $m = \frac{-1}{9}$}\\$

$\textup{Then the slope of the line perpendicular to this line would be \textbf{negative reciprocal of m}.}\\$i.e.,$ \textup{Slope of the perpendicular line would be $m_1 = \frac{-1}{\frac{-1}{9}}$}\\$\implies m_1 = 9$\\$

$\textup{The perpendicular line passes through the point $(3,6)$}\\\textup{Using the \textbf{point-slope formula}, we get:}\\$

$$$ y - y_1 = m(x - x_1) $$$ \implies y - 6 = 9(x - 3) $\\\textup{After solving this reduces to $y = 9x + 21$ }$

8 0

3 years ago

Solve The Equation <br> 4x×9y=7<br> 4x-9y=9

hoa [83]

Answer:

$\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}$

$4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}$

8 0

2 years ago

What figure can be made with exactly 420 squares?

Natali [406]

5. The 5th figure will have 30 tiles.
6. The 6th figure will have 42 tiles.
7. The pattern is non-linear (quadratic).
8. The 20th figure can be made with 420 tiles.

_____
The Nth figure is made with n*(n+1) tiles. To answer question 8, you must solve
.. n(n +1) = 420
.. n^2 +n -420 = 0
.. (n +21)(n -20) = 0
.. n = 20 or -21 . . . . the negative solution is extraneous

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2 years ago

2. At the local park, there is an annual fair that

mafiozo [28]

Answer:

132 children and 88 adults

Step-by-step explanation:

let x represent the amount of kids and y represent the amount of adults.

since the problem says there was a total of 220 people at the fair an equation can be made

x+y=220

the problem tells that each childrens ticket was 1.5$ and each adult ticket was $4 and that a total of $550 was made that day, we can use the knowledge to make an equation:

1.5x + 4y = 550

using the equations we can make this systems of equations:

1.5x + 4y =550

x + y =220

solve the systems of equations by subracting y on both sides of th bottom equation:

x=220-y

since x is equivant to 220-y it can be substitued for x in the first equation to make this:

1.5(220-y)+4y =550

--solve for y--

y=88 - there were 88 adults

substute 88 for y in the second equation

x+88=220

--solve for x--

x=138 - there were 132 children

7 0

2 years ago