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irina [24]
3 years ago
7

Solve by factorisation 2x2 + 3x - 20 = 0

Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

Step-by-step explanation:

4 + 3x -20 = 0

3x - 16 = 0

3x = 16

x = 16/3

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Step-by-step explanation:

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Which of these strategies would eliminate a variable in the system of equations?
Lubov Fominskaja [6]

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B

Step-by-step explanation:

2x-5y=13.........(1) × 3

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6x - 15y = 39

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Can you guys figure out the linear function for this table, please?
Bess [88]

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y = 6x + 10

Step-by-step explanation:

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Write the equation ∣4−r/3∣=7 as two separate equations, and enter each equation in its own answer box below. Neither of your equ
Naddik [55]

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Step-by-step explanation:

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6 0
3 years ago
How many multiples of 4 are there in {n; 37< n <1001}?
s2008m [1.1K]
Let's begin by listing the first few multiples of 4:  4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44.  So, between 1 and 37 there are 9 such multiples:  {4, 8, 12, 16, 20, 24, 28, 32, 36}.  Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

<span>How many multiples of 4 are there in {n; 37< n <101}?  We could list and then count them:  {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval.  Try subtracting 40 from 100; we get 60.  Dividing 60 by 4, we get 15, which is 1 less than 16.  So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
   -40
-------
 960

Dividing this by 4, we get 240.  Adding 1, we get 241.

Finally, subtract 9 from 241:  We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number? </span>

5 0
3 years ago
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