Answer:
a median=31
first quartile=10.75
third quartile=34
b median=31
first quartile=10.75
third quartile=34.75
c median=31
first quartile=12
third quartile=34.75
d median=31
first quartile=12
third quartile=34
Step-by-step explanation:
mark brainliest please
just took a lesson on it
Answer:
B) The earthquake measuring 4.5 on the Richter scale is about 32 times more intense than an earthquake measuring 3.
Step-by-step explanation:
Let Ra = log(Ia/Io), and Rb = log(Ib/Io). Then for ...
Ra - Rb = 4.5 -3.0 = 1.5
log(Ia/Io) -log(Ib/Io) = 1.5 . . . . . . . . . . . substitute the given expressions
(log(Ia) -log(Io)) -(log(Ib) -log(Io)) = 1.5 . . . expand the logs
log(Ia) -log(Ib) = 1.5 . . . . simplify
log(Ia/Ib) = 1.5 . . . . . . . . write as a single log
Ia/Ib = 10^1.5 ≈ 32 . . . . take the antilog
The ratio of intensities is about 32, corresponding to choice B.
Answer:
2 kittens per crate
Step-by-step explanation:
The kittens in a room at an animal shelter are arranged in five crates, as shown.
The manager of the shelter wants the kittens distributed equally among the crates. How might that be done? How many kittens will end up in each crate?
Crate 1 = 2 kittens
Crate 2 = 1 kitten
Crate 3 = 4 kittens
Crate 4 = 3 kittens
Crate 5 = 0 kitten
Total kittens = 2 + 1 + 4 + 3 + 0
= 10 kittens
To distribute them equally among the crates, divide the number of kittens by the number of crates
Kitten per crate = number of kittens / number of crates
= 10 kittens / 5 crates
= 2 kittens per crate
Kitten per crate = 2 kittens per crate
Answer:
Step-by-step explanation:
let their ages be x,y,z and x>y>z
x+y+z=74 ...(1)
x=(y+z)-12
or x-y-z=-12 ...(2)
y=z+5 ...(3)
add (1) and (2)
2x=62
x=62/2=31
from (1)
31+y+z=74
y+z=74-31=43
substitute from (3)
z+5+z=43
2z=43-5=38
z=38/2=19
y=19+5=24
so their ages are 31,24 and 19