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3 years ago

What is the growth or decay and the percentage rate of Y=23(0.292)^x

Mathematics

1 answer:

torisob [31]3 years ago

5 0

Answer:

So the decay percentage rate is of 70.8%

Step-by-step explanation:

An exponentil function has the following format:

$y = ca^{x}$

In which c is a constant.

If a>1, we have that a = 1 + r and r is the growth rate.

If a<1, we have that a = 1 - r and r is the decay rate.

In this problem:

a = 0.292

A is lesser than 1, so r is the decay rate.

1 - r = 0.292

r = 1 - 0.292

r = 0.708

So the decay percentage rate is of 70.8%

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3 years ago

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3 years ago

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3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$