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sleet_krkn [62]
3 years ago
13

Without calculating, which has a bigger volume. A cube that has a length, width, and height of 18 m. Or a sphere with a radius o

f 9 m? Explain.
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0

Weird. A period appears above this... huh.

Answer:

[Th]e cube has a greater value.

Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4\pir^2 when r = 9? And here's how to solve that.

Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?

A=6(18)^2 Substitute numbers.

A=6(324) Solve ex[p]onents.

A=1944 Mult[i]ply.

So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4\pir^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.

A=4(3.14)(9)^2 Subst[i]tute numbers.

A=4(3.14)(81) Solve expone[n]ts.

A=12.56(81) Multip[ly].

A=1017.36 Multiply again[.]

Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.

And PLEASE don't copy this guys. Make your own iteration. Change it up!

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2 years ago
Please help im stuck on this question​
VARVARA [1.3K]

Answer:

(12,0)

Step-by-step explanation:

slope m=

\frac{54-36}{27-22} =\frac{18}{5}

y-36=\frac{18}{5}(x-22)\\\\5y-180=18x-396\\\\y=\frac{18x}{5} -\frac{46}{5}

0=\frac{10}{5}x-\frac{46}{5}\\\\x=\frac{216}{18}   =12

hope it helps...

have a great day

7 0
3 years ago
What is the equation in standard form of an ellipse centered at the origin and vertex (1,0) and focus (4,0)
Dmitriy789 [7]
The correct question is
<span>What is the equation in standard form of an ellipse centered at the origin and vertex (4,0) and focus (1,0)
</span>

we know that
<span>Standard form of equation for an ellipse with horizontal major axis is
(x-h)</span>²/a²+(y-k)²/b²=1
the center is the origin
so
(h,k) is (0,0)<span>length of horizontal major axis------> 8=2a-----> a=4
a</span>²=16
c=1 (distance from center to focal point)
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b²=a²-c²-----> b²=16-1----> b²=15

the equation is
(x)²/16+(y)²/15=1

the answer is
(x)²/16+(y)²/15=1


3 0
3 years ago
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