Answer:
Step-by-step explanation:
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<u>hope it helps...</u>
<u>have a great day!!</u>
Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Answer:
Parallel
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
4x + 2y = 10 ( subtract 4x from both sides )
2y = - 4x + 10 ( divide through by 2 )
y = - 2x + 5 ← in slope- intercept form
with slope m = - 2
and
y = - 2x + 15 ← is in slope- intercept form
with slope m = - 2
• parallel lines have equal slopes
then the 2 lines are parallel
Answer:
d
Step-by-step explanation:
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Answer:
Option A - Neither. Lines intersect but are not perpendicular. One Solution.
Option B - Lines are equivalent. Infinitely many solutions
Option C - Lines are perpendicular. Only one solution
Option D - Lines are parallel. No solution
Step-by-step explanation:
The slope equation is known as;
y = mx + c
Where m is slope and c is intercept.
Now, two lines are parallel if their slopes are equal.
Looking at the options;
Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.
Thus,the lines are parrallel, no solution.
Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.
Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.
Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.
Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.
Option B falls into this category.
