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Alex787 [66]
3 years ago
15

Please answer the question from the attachment.

Mathematics
1 answer:
kompoz [17]3 years ago
3 0
C - 11 /9 = 9

Multiply both sides by 9

c - 11 = 81

add 11 to each side to isolate c

c = 81 + 11 = 92
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The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

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2x^2 + x - 6 = 0

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\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
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Help please and thanks !!
drek231 [11]

Answer:

Step-by-step explanation:

I think you put it in the middle

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