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3 years ago

Solve for the missing side length, rounded to the nearest tenth.

Mathematics

1 answer:

zaharov [31]3 years ago

6 0

Answer: 5.2 mm 7 mm About mm

Step-by-step explanation: There are several ways to determine the missing information in a right triangle. Once you know all the side lengths, you can compute all of the trigonometric functions. Solving the equation and rounding to the nearest tenth gives you .

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(1) Cos AcosecA=cot A

Mashutka [201]

Answer:

The Basic Identities are :

$cosec(A) = \frac{1}{ \sin(A) }$

$\tan(A) = \frac{ \sin(A) }{ \cos(A) }$

$\cot(A) = \frac{1}{ \tan(A) } = \frac{ \cos(A) }{ \sin(A) }$

So for this question :

$\cos(A)cosec(A) = \cot(A)$

$l.s.h = \cos(A) \times \frac{1}{ \sin(A) }$

$l.s.h = \frac{ \cos(A) }{ \sin(A) }$

$l.sh = \cot(A) \: (proven)$

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3 years ago

1.The diameter of a circle is 20m. Find the circumference to the nearest tenth

Temka [501]

Answer:

62.8

Step-by-step explanation:

The formula for circumference is 2(pi)r

Let's plug in the values.

Well, we know the diameter, and since the radius is 1/2 the diameter, but then you multiply by 2 again, you don't have to change anything. Therefore, another formula is (pi)<em>d</em>

3.14 x 20

= 62.8 is your answer. And the answer is already rounded to the nearest tenth, so nothing is left to do!

<em>Hope this helps!</em>

3 0

2 years ago

6x - 3 = 3( 2x - 1 ) what is the answer need it fast please and thank you

Andrew [12]

Answer:

Any number for x will work

Step-by-step explanation:

6x-3=3(2x-1)

expand

6x-3=6x-3

add three to both sides

6x=6x

simplify

x=x

Therefore any number for x will work

6 0

2 years ago

Read 2 more answers

Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop

Archy [21]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}$

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olga_2 [115]

Answer:

Step-by-step explanation:

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