Answer:
hey,
ur question is wrong,
base of triangle can never be longer than hypotenuse,and you have told base is twice of hypotenuse,
if hypotenuse is twice of base, then solution is give below, in picture,
and answer is 1/2
<u>In sentence 7, the </u><u>phrase</u><u> by all accounts is best replaced by </u><u>however.</u>
Correct option is A
- The sentence that precedes 7 states something that is in contrast with it.
- Therefore 'by all accounts' in sentence should be changed to 'however' as it is generally used to present something that is different from or contrasts with the previous statement.
- Thus A is the best answer. The other options are incorrect because they do not convey the contrast that is required in the given context.
What is a phrase in grammar?
- In syntax and grammar, a phrase is a group of words which act together as a grammatical unit.
- For instance, the English expression "the very happy squirrel" is a noun phrase which contains the adjective phrase "very happy".
- Phrases can consist of a single word or a complete sentence.
Learn more about Phrases
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Using the normal distribution, we have that:
- The distribution of X is
.
- The distribution of
is
.
- 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
- 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem, the parameters are given as follows:

Hence:
- The distribution of X is
.
- The distribution of
is
.
The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:
X = 58:


Z = 0.05.
Z = 0.05 has a p-value of 0.5199.
X = 55:


Z = -0.1.
Z = -0.1 has a p-value of 0.4602.
0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
For the sample of 17 movies, we have that:
X = 58:


Z = 0.19.
Z = 0.19 has a p-value of 0.5753.
X = 55:


Z = -0.38.
Z = -0.38 has a p-value of 0.3520.
0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
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The value of the discriminant is
12.
Since the discriminant is greater than zero, the equation has
two real solutions.