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3 years ago

Determine the number of solutions for the equation shown below.

Mathematics

1 answer:

Stolb23 [73]3 years ago

6 0

Answer:

A. 0

Step-by-step explanation:

Nothing can be equal to itself if you subtract 9 from it.

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12. What's

Sholpan [36]

Answer:

C.)

Step-by-step explanation:

Denominator is the bottom part of a fraction

3 0

3 years ago

Almost done just need to get to 80

Vilka [71]

Answer:

60%

Step-by-step explanation:

6/10 of the shape is green, meaning that it is 60 %.

8 0

3 years ago

Read 2 more answers

Indicate a general rule for the nh term of this sequence. 12a, 15a, 18a, 21a, 24a,...

adelina 88 [10]

Answer:

The general rule for the nth term of this sequence will be:

$a_n=3na+9a$

Step-by-step explanation:

Given the sequence

12a, 15a, 18a, 21a, 24a,...

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

Here,

a₁ = 12a

computing the differences of all the adjacent terms

d = 15a-12a = 3a, d = 18a-15a=3a, d=21a-18a=3a, d=24a-21a=3a

using the nth term formula

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = 12a, d = 3a

$a_n=12a+\left(n-1\right)3a$

$=12a+3na-3a$

$=3na+9a$

Therefore, the general rule for the nth term of this sequence will be:

$a_n=3na+9a$

6 0

3 years ago

He copper in copper tubing has a volume of 98 cm^3 and a mass of 872.2 g.

lara31 [8.8K]

Answer:

Step-by-step explanation:

The density of an object is given by the mass divided by the volume

Density: 872.2/98

= 8.90 grams/cm^3 (rounded to 3 significant figures)

4 0

3 years ago

A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is

seraphim [82]

Answer:

a) The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at 0.01% level of significance

They score is above 24 on the math portion of the exam

b)

Null Hypothesis: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

Alternative Hypothesis: H₁: μ ≠ 24

Step-by-step explanation:

Step(i):-

Given random sample 'n' = 250

Given data sample mean x⁻ = 24.5

Standard deviation = 3.3

Null Hypothesis: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

Alternative Hypothesis: H₁: μ ≠ 24

test statistic

$Z = \frac{x^{-} - mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{24.5 - 24}{\frac{3.3}{\sqrt{250} } } = \frac{0.5}{0.2087} = 2.397$

a) 99% or 0.01% level of significance

Level of significance ∝ = 0.01

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.005} =2.576$

The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at 0.01% level of significance

They score is above 24 on the math portion of the exam

b) 95% or 0.05% level of significance

Level of significance ∝ = 0.05

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96$

The Z -value 2.397 > 1.96 at 95% or 0.05% level of significance

Null hypothesis is Rejected at 0.05% level of significance

They score is below 24 on the math portion of the exam

6 0

3 years ago