Determine the points of intersection of the equation circumference x² + (y-3) ² = 25 with the coordinate axes.
2 answers:
Answer:
(0, -2), (4, 0), (0, 8), (-4, 0)
Step-by-step explanation:
The y-intercepts are found by solving for y when x=0.
(y -3)² = 25
y -3 = ±5 . . . . . take the square root
y = 3 ± 5 = {-2, 8}
The x-intercepts are found by solving for x when y=0.
x² +(0-3)² = 25
x² = 16 . . . . . . . . subtract 9
x = ±4 . . . . . . . . .take the square root
The y-intercepts are (0, -2) and (0, 8).
The x-intercepts are (-4, 0) and (4, 0).
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