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nikitadnepr [17]
2 years ago
13

. XYZ has vertices X (–5, 2), Y (0, –4), and Z (3, 3). What are the vertices of the image of X’Y’Z’ under the translation (x, y)

→ (x + 7, y – 5) ?
Mathematics
1 answer:
Katen [24]2 years ago
6 0

Answer:

X' = (2, -3)

Y' = (7, -9)

Z' = (10, -2)

Step-by-step explanation:

to find the translation of each point substitute the x and y with the the numbers

eg; X ( -5,2) the x is 5 and the y is 2

so -5 + 7 = 2 (the x value)

2 - 5 = -3 ( the y value)

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Solve y = −23(x + 9) + 4 for x when y = 0.
Vlad [161]

Answer:

x = -203/23

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

y = -23(x + 9) + 4

y = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in <em>y</em>:                                                                                                  0 = -23(x + 9) + 4
  2. [Subtraction Property of Equality] Subtract 4 on both sides:                        -4 = -23(x + 9)
  3. [Division Property of Equality] Divide -23 on both sides:                                4/23 = x + 9
  4. [Subtraction Property of Equality] Subtract 9 on both sides:                        -203/23 = x
  5. Rewrite:                                                                                                             x = -203/23
3 0
2 years ago
Read 2 more answers
3. *
Sati [7]

Answer:

A first numbers cant be same

5 0
2 years ago
Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate
kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality x^{2}-5x+4\leq 0. To do that, factorize, then we have that (x-4)(x-1)\leq 0. This implies that

x-1\leq 0\, \text{and}\, x-4\geq 0

or

x-1 \geq 0\, \text{and}\, x-4\leq 0

In the first case the solution is the empty set \emptyset. In the second case the solution is the interval 1\leq x \leq 4. Now we have that

A=[1,4]

B=(3,5)

C=(3,4].

To show that A\cap B\subseteq C consider x\in A\cap B. Then 1\leq x \leq 4\, \text{and}\, 1, this implies that 3, then x\in C. Now, to show that C\subseteq A\cap B consider x\in C, then 3, then 1\leq x \leq 4\, \text{and}\, 3, then x\in [1,4] \, \text{and}\, x\in (3,5), this implies that x\in A\cap B.

Observe the image below.

7 0
3 years ago
The area of triangle PQR is 273 cm. Given that PQ = 12.8cm and PQR = 107°, find QR.​
storchak [24]

\text{Area of triangle} = \dfrac 12 \times PQ \times QR \times  \sin \angle PQR \\\\\\\implies  273= \dfrac 12 \times 12.8 \times QR \times \sin 107^{\circ}\\\\\implies 273 = 6.4 \sin 107^{\circ}  \times QR\\\\\\\implies QR = \dfrac{273}{6.4 \sin 107^{\circ}} = 44. 606~~ \text{cm}

8 0
2 years ago
Rewrite 1/(√x-5) in an equivalent form with a rational expression in the denominator.
sladkih [1.3K]

Answer:

1/(√x-5)*(√x+5)/(√x+5)

Step-by-step explanation:

1/(√x-5)*(√x+5)/(√x+5)

4 0
3 years ago
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