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nikitadnepr [17]
3 years ago
13

. XYZ has vertices X (–5, 2), Y (0, –4), and Z (3, 3). What are the vertices of the image of X’Y’Z’ under the translation (x, y)

→ (x + 7, y – 5) ?
Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

X' = (2, -3)

Y' = (7, -9)

Z' = (10, -2)

Step-by-step explanation:

to find the translation of each point substitute the x and y with the the numbers

eg; X ( -5,2) the x is 5 and the y is 2

so -5 + 7 = 2 (the x value)

2 - 5 = -3 ( the y value)

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Considering the inequality

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SOLVING THE INEQUALITY  -4x+7\ge \:27  TO MATCH OPTION B

Considering the inequality

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