Given:
The given equation is
To find:
All the real solutions.
Solution:
We have,
It can be written as
Using zero product property, we get
and 
and 
and 
We know that is an imaginary number because there is a negative sign under the square root.
Therefore, is the only real solution of the given equation.
Answer:
Area of a circle=πr²
radius is half of the diameter
1/2×2=1
π1²
22/7×1
3.1415926535897932
~3.14
Answer: (going down the table)
1) 5, 8, 6, 1
2) 2, 6, 10, 2
Step-by-step explanation:
count how many are in that bracket.
EG:
1) the amount of numbers between 5 and 10, including 5
etc
Answer:
The answer would be A. 1 1/5
Step-by-step explanation:
1 8/40 Simplify to 1 1/5
48/40 = 1 8/40
The answer to this question is above.
Hope this helps.
If Stuart starts with -$54.19 then gains $70.82, you have to add the gained amount to the origin amount. Since the origin amount is negative, you can also subtract the origin amount from the gained amount to find the amount left at the end of the month.
Add 70.82 to -54.19
-54.19 + 70.82 = 16.63
<u>Alternative method:</u>
First, subtract 54.19 from 70.82.
70.82 - 54.19 = 16.63
Add 54.19 to -54.19, bringing you to 0.
-54.19 + 54.19 = 0
Now add the remaining 16.63.
0 + 16.63 = 16.63
<h2>Answer:</h2>
<u>Stuart will have </u><u>$16.63</u><u> at the end of this month.</u>
