Let
rA--------> radius of the circle A
rB-------> radius of the circle B
SA------> the area of the sector for circle A
SB------> the area of the sector for circle B
we have that
rA=5/2 ft
rB=9/2 ft
rA/rB=5/9-----------> rB/rA=9/5
SA=(25/36)π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(9/5) ^2*(25/36)π--->
<span>SB----------- > (81/25)*(25/36)------ > 81/36------
> 9/4π ft²</span>
the answer is
<span>the measure of the sector for circle B is (9/4)π ft²</span>
2x2x2x2x2 hope this helps
Answer:
7 (StartFraction x over 8 EndFraction) + three-fourths = negative 6
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Because u need to find the LCD and the LCD of 4 and 7 is 28
