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Dimas [21]
2 years ago
8

-12divided by 3 help me plz

Mathematics
2 answers:
I am Lyosha [343]2 years ago
6 0

Answer:

-4

Step-by-step explanation:

podryga [215]2 years ago
5 0

Answer:

-4

Step-by-step explanation:

  1. Write it out: -12 ÷ 3
  2. -12 ÷ 3 = -4
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Don has been tracking the population of a town. The population was 7,220 last year and has been increasing by 1.45 times each ye
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7220*1.45^x where 1.45 is the rate of growth.

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2 years ago
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At the beginning of spring, Taylor planted a small sunflower in her backyard. When it was first planted, the sunflower was 25 in
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

The sunflower then began to grow at a rate of 2 inches per week. This means that the rate of growth of the sunflower is in arithmetic progression. We would apply the formula for determining the nth term of an arithmetic sequence which is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 25 inches

d = 2 inches

To determine the height after 7 weeks, T7

n = 7

T7 = 25 + 2(7 - 1)

T7 = 25 + 12

T7 = 37 inches

To determine the height after w weeks, Tw

n = w

Tw = 25 + 2(w - 1)

Tw = 25 + 2w - 2

Tw = 23 + 2w

6 0
3 years ago
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How do you solve the division problem 456÷5?
stiv31 [10]
To find the exact value using trigonometric identities
Exact form 456 divide a by 5
Decimal form 91.2
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4 0
2 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
2 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
2 years ago
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