Answer:
Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer
Explanation:
Hope this helps :)
Aluminium is the element you are looking for
Answer:
Explanation:
Formal charge of ICl₂⁻
Formal charge = group no - ( no of non bonding electrons +no of bonds)
In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.
Each of chlorine atoms also contains 7 valance electrons like iodine.
So formal charge of chlorine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
So formal charge of iodine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 5 + 2 )
=0
Formal charge of ICl₂⁺
In this case , central iodine will have only 6 valence electrons due to absence one electron.
So formal charge of chlorine in ICl₂⁺
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
formal charge of iodine in in ICl₂⁺
7 - ( 4 + 2)
= 1
Answer:
4.16
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that:
pKa = 3.86
Given, concentration of acid = [acid] = 0.4 M
concentration of base = [base] = 0.8 M
So,
pH=3.86+log(0.8/0.4) = 4.16
Answer:
30
According to the Law of Conservation of Matter, there will be 30 atoms of product in the reaction.
LAW OF CONSERVATION OF MATTER:
The law of conservation of matter states that matter can neither be created nor produced in a chemical reaction.
This further means that the amount of matter in the reactant of a reaction must equate that of the products.
Hence, if 10 atoms of carbon (C) react with 20 atoms of oxygen (O), there will be 10 + 20 = 30 atoms of product in this reaction.
Therefore, According to the Law of Conservation of Matter, there will be 30 atoms of product in the reaction.
