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netineya [11]
3 years ago
11

Which of the following is true about the frequencies of electromagnetic radiation

Chemistry
1 answer:
Semmy [17]3 years ago
3 0
<h2>Answer:Ultraviolet waves have higher frequencies than radio waves.</h2>

Explanation:

The waves arranged in increasing order of frequency are radio waves,infrared waves,x-rays,ultraviolet waves.

Option A:

Ultraviolet waves have higher frequencies than radio waves.This agrees with the above order.

Option B:

X-rays have lower frequencies than infrared waves.This does not agree with the above order.

Option C:

Radio waves have higher frequency than x-rays.This does not agree with the above order.

Option D:

Gamma rays have lower frequencies than ultraviolet waves.This does not agree with the above order.

So,option A is correct.

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Coefficients are used in a chemical formula to show the number of each element. True or False
ANTONII [103]

Answer:

The same number of each element present before the reaction takes place must also be present on the product side of the equation. Coefficients are placed in front of a chemical formula to show the number of moles of that substances that are necessary for the reaction to occur.

Explanation:

5 0
3 years ago
Why do you think it is advantageous to use inert electrodes in the electrolysis process? ​
olga nikolaevna [1]

Answer:

The advantage of this technique is that purified water as well as deposited metals can be re-used. It is necessary to use an inert electrode, such as platinum, because there is no metal present to conduct the electrons from the anode to the cathode.

5 0
2 years ago
at 55 years what mass remains of a 200.0 g sample of a radioactive isotope with a half life of 10.0 years
Harman [31]

Answer:

4.419 g

Explanation:

     55 years is 5.5 half lives

200 g   *   (1/2)^5.5 = 4.419 g

3 0
1 year ago
Calculate the standard free-energy change at 25 ∘C for the following reaction:
lianna [129]

Answer:

Standard free-energy change at 25^{0}\textrm{C} is -3.80\times 10^{2}kJ/mol

Explanation:

Oxidation: Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)

Reduction: Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)

--------------------------------------------------------------------------------------

Overall: Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)

Standard cell potential, E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}

So, E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V

We know, standard free energy change at 25^{0}\textrm{C}(\Delta G^{0}): \Delta G^{0}=-nFE_{cell}^{0}

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, \Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol

8 0
3 years ago
Read 2 more answers
Can someone help me balance this equation please?<br> Br2 + S2O32– + H2O → Br1– + SO42– + H+
tamaranim1 [39]

Explanation:

Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e

7 0
2 years ago
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