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4 years ago

Which of the following is true about the frequencies of electromagnetic radiation

Chemistry

1 answer:

Semmy [17]4 years ago

3 0

<h2>Answer:Ultraviolet waves have higher frequencies than radio waves.</h2>

Explanation:

The waves arranged in increasing order of frequency are radio waves,infrared waves,x-rays,ultraviolet waves.

Option A:

Ultraviolet waves have higher frequencies than radio waves.This agrees with the above order.

Option B:

X-rays have lower frequencies than infrared waves.This does not agree with the above order.

Option C:

Radio waves have higher frequency than x-rays.This does not agree with the above order.

Option D:

Gamma rays have lower frequencies than ultraviolet waves.This does not agree with the above order.

So,option A is correct.

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Finish this formula: Speed = _______ divided by time

Alexus [3.1K]

Answer:

Distance

Explanation:

Speed= Distance/ Time

7 0

3 years ago

Read 2 more answers

Help with 5b. Full explanation please

larisa86 [58]

Not elementary school work

8 0

3 years ago

If anyone can get this question, 20 points for you!

torisob [31]

Answer:

Light

Explanation:

The discovery of light from the other side of a black hole was predicted by Einstein's theory of general relativity. ... The research began with a slightly different aim of a more common light formed by a black hole: the corona which wraps around the outside of it, formed as material falls in.

6 0

2 years ago

What is the mass in grams of 0.280 mole sample of sodium hydroxide NaOH

vivado [14]

Answer:

The mass of 0.280 mole sample of sodium hydroxide NaOH is 11.2 grams.

Explanation:

To know the mass in grams of 0.280 moles of sample of sodium hydroxide NaOH, you must know the molar mass of the compound, that is, the mass of one mole of a substance, which can be an element or a compound.

So you know:

Na: 23 g/mole
O: 16 g/mole
H: 1 g/mole

So, the molar mass of NaOH is:

NaOH= 23 g/mole + 16 g/mole+ 1 g/mole= 40 g/mole

Then the following rule of three can be applied: if in 1 mole of sodium hydroxide there are 40 grams, in 0.280 moles how much mass is there?

$mass=\frac{0.28 moles*40 grams}{1 mole}$

mass= 11.2 grams

<u><em>The mass of 0.280 mole sample of sodium hydroxide NaOH is 11.2 grams.</em></u>

4 0

3 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago