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g100num [7]
3 years ago
5

HELP PLEASE!

Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

Option C: The line y = x

Step-by-step explanation:

Let us take an ordered pair (x, y) of a function. Then the ordered pair of its inverse function would be (y, x).

That is to say, when we reflect a point (x, y) across the line y = x we get the point (y, x).

Note that since, this function is invertible, it is both 'one - one' and 'onto'.

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What is, 3 - (1/3) to the power of 4?
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Answer:

3-(1/3)^4 = 242/81

Step-by-step explanation

to raise a fraction to a power, raise the numerator and denominator to that power. Making it 3-1/81

then calculate the difference, making your answer 242/81 (or 2 wholes and 80/81)

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3 years ago
Definition of variability
SashulF [63]
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A car dealership pays $8,350 for a car. They mark up the price by 18% to get the retail price. What is the retail price of the c
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Step-by-step explanation:

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3 years ago
The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are
Mashcka [7]

Answer:

The area of triangles are 16 cm^2 and 49 cm^2

Step-by-step explanation:

we know that

If two figures are similar, the ratio of its perimeters is equal to the scale factor and the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the smaller triangle in square centimeters

y ----> the area of the larger triangle in square centimeters

we know that

z=\frac{4}{7}

\frac{x}{y}=z^2

so

\frac{x}{y}=(\frac{4}{7})^2      

\frac{x}{y}=\frac{16}{49}

x=\frac{16}{49}y -----> equation A

x+y=65 ----> equation B

solve the system by substitution

substitute equation A in equation B

\frac{16}{49}y+y=65

solve for y

\frac{65}{49}y=65

y=49\ cm^2

Find the value of x

x=\frac{16}{49}(49)

x=16\ cm^2

therefore

The area of triangles are 16 cm^2 and 49 cm^2

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4 years ago
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What is the solution of -x+4>2
Svetradugi [14.3K]

There is no single solution but there is a group of solutions also known as the interval.

-x+4>2 \\-x>-2 \\x

This can be written with an interval.

x\in(-\infty, 2)

Hope this helps.

r3t40

6 0
4 years ago
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