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3 years ago

What is the surface area?

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

The formula of the Surface Area of a cilinder:

$SA=2\pi rh+2\pi r^2$

r = 2 yd

h = 1 yd

Substitute:

$SA=2\pi\cdot2\cdot1+2\pi\cdot2^2=4\pi+8\pi=12\pi\ yd^2$

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vlabodo [156]

Answer : a
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3 years ago

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Find the coordinates of the midpoint AB. 1) ( -2,4), (4,0) THANK YOU!! And it's worth a lot of points if I get it right.

AnnyKZ [126]

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3 years ago

Please help me with this

kupik [55]

Answer:

–x² + 12x + 5

Step-by-step explanation:

x² + 3x

–2x² + 9x + 5

The sum of the above expression can be obtained as follow:

.... x² + 3x

+ –2x² + 9x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

–x² + 12x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Thus, the sum of x² + 3x and –2x² + 9x + 5 is –x² + 12x + 5

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3 years ago

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aksik [14]

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2 years ago

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

7 0

3 years ago