<u>there </u><u>a</u><u>r</u><u>e</u><u> </u><u>3</u><u>1</u><u>4</u><u>.</u><u>5</u><u> </u><u>b</u><u>o</u><u>y</u><u>s</u><u> </u><u>in the school </u><u>.</u>
Answer:
Solution given
let boys be x and girls be y.
now
according to the question;
x+y=575
and
y=x-54
substituting value of y in equation 1.
x+x-54=575
2x=575+54
x=629/2
x=314.5
Answer:
x=4± 5sqrt(2)
Step-by-step explanation:
x^2 – 8x – 34 = 0
To complete the square Add 34 to each side
x^2 -8x -34+34=0+ 34
Take the coefficient of x, and divide by 2
-8/2 =-4
Then square it and add it to each side
(-4)^2 =16
x^2 – 8x +16 = 34+16
x^2 – 8x +16 = 50
We replace the left side with (x + the coefficient of x/2)^2
(x -4)^2=50
Take the square root of each side
sqrt((x -4)^2)=±sqrt(50)
x-4 = ±sqrt(25*2)
x-4 = ±sqrt(25)*sqrt(2)
x-4 = ±5sqrt(2)
Add 4 to each side
x=4± 5sqrt(2)
You are enough I know this is not what you expect but just know YOU are enough you are awesome and amazing whatever you are going through just know YOU are enough
Answer:
y=-(3/5)x+5.8
Step-by-step explanation: