Answer:
Na = 5.911 ×
atoms/cm³
Explanation:
given data
silver-gold alloy C Au = 17 wt%
densities ρ Au = 19.32 g/cm³
densities ρ Ag = 10.49 g/cm³
atomic weights A Au = 196.97 g/mol
atomic weights A Ag = 107.87 g/mol
solution
we will apply here formula for number of gold atoms that is
Na =
............................1
here NA is Avogadro's number and ρ is density of two element and A is atomic weight
put here value
Na =
Na = 5.911 ×
atoms/cm³
Answer:
T surface = 3.9°C
Explanation:
given data
emissivity 0.6
absorptivity = 0.2
solar radiation is incident rate = 1200 W/m²
solution
we get here surface temperature by equality of emitted and absorbed heat rate that is
Q (absorbed) = Q (heat ) .................1
α Qinc =
T surface =
..........................2
put here value and we get
T surface =
T surface = 276.9 K
T surface = 3.9°C
Answer:I don’t know.
Explanation:I work for carrier and we haven’t really gotten into that yet.