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maxonik [38]
3 years ago
6

The development team recently moved a new application into production for the accounting department. After this occurred, the Ch

ief Information Officer (CIO) was contacted by the head of accounting because the application is missing a key piece of functionality that is needed to complete the corporations quarterly tax returns. Which of the following types of testing would help prevent this from reoccurring? (choose one and why)
(A) Security regression testing
(B) User acceptance testing
(C) Input validation testing
(D) Static code testing
Engineering
1 answer:
Novay_Z [31]3 years ago
4 0

Answer: (A) Security regression testing

Explanation:

  The security regression testing is used to prevent the re-occurring process. The regression testing is the type of the testing that intends to affirm that a program or code or application changes has not influenced existing highlights and it keeps up the agenda.

The agenda ought to be similarly identified with necessity that was concluded. By checking this both then relapse testing occurs and this won't reoccurred from next time.

The regression testing improvements groups must ensure that changes, updates and new discharges don't presents imperfections and vulnerabilities that could be misused by the people.

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Describe a simple process
Sunny_sXe [5.5K]

Answer:

Use linking words.

Explanation:

8 0
3 years ago
In your opinion, what is the external opportunity cost of a successful biking company in a community
OleMash [197]

Answer:

The cost of increased rates of accidents/injuries due to road accidents associated with cycling.

Explanation:

Opportunity cost is referred to as an alternative cost which is the value of the other choose left out while settling for a better alternative. External cost will be the cost a society has to bear as a result of a private cost. A successful biking company in a community can led to increased rates of accidents due to road accidents associated with cycling. In addition, the society will have to bear the costs of the threats presented by dangerous car drivers who posse more danger to cyclists as compared to trucks/car drivers.

8 0
3 years ago
An 80-L vessel contains 4 kg of refrigerant-134a at a pressure of 160kPa. Determine (a) the temperature, (b) the quality, (c) th
makvit [3.9K]

Answer:

temperature -15.6 C, quality x=0.646, enthalpy h=667.20 KJ, volume of vapor phase Vg= 79.8 L

Explanation:

property table for R-134a

https://www.ohio.edu/mechanical/thermo/property_tables/R134a/R134a_PresSat.html

at 160 KPa , temperature = -15.66 C

quality x=mass of vapour/ total mass of liq-vap mixture

alternaternately: x=(v-vf)/(vg-vf)    

v=total volume i.e. volume of container"80L"   80L=0.08 cubic meter

vf=vol of liquid phase  vg=vol of vapor phase vf, vg values at 160Kpa

x=(0.08-0.0007437)/(0.1235-0.0007437)=0.646

enthalpy

h=hf+xhfg          hf, hfg values at 160Kpa

h=hf+xhfg=31.2+0.646(209.9)=166.80 KJ/Kg

for 4Kg R-134a h=m(166.80 KJ/Kg )=667.20 KJ

volume of vapor phase

vg at 160Kpa=0.1235 cubic meter for quality=1.

in this case quality=0.646 , so it will occupy 64.6% space of the vapor phase at quality=1.

vol. of vapor phase=0.646*0.1235=0.0798 cubic meter=79.8 L

7 0
3 years ago
The formation of faults in Earth's crust is an effect. What causes faults to form in the crust? Global Positioning System sensor
allsm [11]

Answer: The movement of tectonic plates

Explanation:

Tectonic plates are the part of the earth's crust that both the ocean and land rest on. These plates are constantly moving as a result of currents in the mantle.

These movements cause stress on the surface which has the effect of fracturing rocks and thereby creating/ forming faults in the earth's crust. Sometimes faults form when these plates move away from each other and sometimes they are formed when they push into each other.

7 0
2 years ago
Calculate the availability of a system where the mean time between failures is 900 hours and the mean time to repair is 100 hour
Debora [2.8K]

Answer:

The availability of system will be 0.9

Explanation:

We have given mean time of failure = 900 hours

Mean time [to repair = 100 hour

We have to find availability of system

Availability of system is given by  \frac{mean\time\ of\ failure}{mean\ time\ of\ failure+mean\ time\ to\ repair}

So availability of system =\frac{900}{900+100}=\frac{900}{1000}=0.9

So the availability of system will be 0.9

7 0
3 years ago
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