1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mariarad [96]
3 years ago
13

How many paragraphs are good for an essay

Engineering
2 answers:
zhannawk [14.2K]3 years ago
3 0

Answer:

It depends what type of essay you're writing. Normally you'll want an intro, three body paragraphs and then a conclusion, but if you're writing an argumentative essay you will want an intro par, three body par, a counterclaim and rebuttal par, and a conclusion par.

Explanation:

Typically 5 or 6 paragraphs will work, really just depends what type of essay.

NISA [10]3 years ago
3 0

Answer:

In its simplest form, an essay can consist of three paragraphs with one paragraph being devoted to each section. Proponents of the five paragraph essay say that the body text should consist of three paragraphs, but in reality, it's fine to write more or fewer paragraphs in this section. An essay is split into sections not paragraphs. While shorter essays will often have one paragraph per section most will have multiple. Paragraph and section are not interchangeable terms. If you wish to only have two paragraphs then you will need to make the core point sections into one paragraph. An essay can be pretty much any length, as long as it's relatively short. Some essays are just one paragraph, and some are several pages long. As long as you say what needs to be said, you can write four paragraphs, six paragraphs, or thirty paragraphs. 1500 words is 8 to 15 paragraphs for essays, 15 to 30 paragraphs for easy writing.

Explanation:

You might be interested in
Create an abstract class DiscountPolicy. It should have a single abstract method computeDiscount that will return the discount f
eimsori [14]

Answer:

Java Code was used to define classes in the abstract discount policy,The bulk discount, The buy items get one free and the combined discount

Explanation:

Solution

Code:

Main.java

public class Main {

public static void main(String[] args) {

  BulkDiscount bd=new BulkDiscount(10,5);

BuyNItemsGetOneFree bnd=new BuyNItemsGetOneFree(5);

CombinedDiscount cd=new CombinedDiscount(bd,bnd);

System.out.println("Bulk Discount :"+bd.computeDiscount(20, 20));

  System.out.println("Nth item discount :"+bnd.computeDiscount(20, 20));

 System.out.println("Combined discount :"+cd.computeDiscount(20, 20));    

  }

}

discountPolicy.java

public abstract class DiscountPolicy

{    

public abstract double computeDiscount(int count, double itemCost);

}    

BulkDiscount.java  

public class BulkDiscount extends DiscountPolicy

{    

private double percent;

private double minimum;

public BulkDiscount(int minimum, double percent)

{

this.minimum = minimum;

this.percent = percent;

}

at Override

public double computeDiscount(int count, double itemCost)

{

if (count >= minimum)

{

return (percent/100)*(count*itemCost); //discount is total price * percentage discount

}

return 0;

}

}

BuyNItemsGetOneFree.java

public class BuyNItemsGetOneFree extends DiscountPolicy

{

private int itemNumberForFree;

public BuyNItemsGetOneFree(int n)

{

  itemNumberForFree = n;

}

at Override

public double computeDiscount(int count, double itemCost)

{

if(count > itemNumberForFree)

return (count/itemNumberForFree)*itemCost;

else

  return 0;

}

}

CombinedDiscount.java

public class CombinedDiscount extends DiscountPolicy

{

private DiscountPolicy first, second;

public CombinedDiscount(DiscountPolicy firstDiscount, DiscountPolicy secondDiscount)

{

first = firstDiscount;

second = secondDiscount;

}

at Override

public double computeDiscount(int count, double itemCost)

{

double firstDiscount=first.computeDiscount(count, itemCost);

double secondDiscount=second.computeDiscount(count, itemCost);

if(firstDiscount>secondDiscount){

  return firstDiscount;

}else{

  return secondDiscount;

}

}  

}

6 0
4 years ago
Two routes connect an origin and a destination. Routes 1 and 2 have performance functions t1 = 2 + X1 and t2 = 1 + X2, where the
Musya8 [376]

Solution :

Given

$t_1=2+x_1$

$t_2=1+x_2$

Now,

$P(h

$0.4=1-P(h \geq5)$

$0.6=P(h \geq5)$

$0.6= e^{\frac{-x_1 5}{3600}}$

Therefore,   $x_1=368 \ veh/h$

                        $=\frac{368}{1000} = 0.368$

Given,   $t_1=2+x_1$

                 = 2 + 0.368

                 = 2.368 min

At user equilibrium, $t_2=t_1$

∴  $t_2$ = 2.368 min

$t_2=1+x_2$

$2.368=1+x_2$

$x_2 = 1.368$

$x_2 = 1.368 \times 1000$

    = 1368 veh/h

7 0
3 years ago
I need your help to answer in the picture plss help me!​
Aloiza [94]

this looks like its the different phases of a single cylinder 4 stroke engine what are you doing in the picture or assignment though matching the numbers to the descriptions on the side?

3 0
3 years ago
Using the Rayleigh criterion, calculate the minimum feature size that can be resolved in a system with a 0.18 NA lens when g-lin
Vladimir79 [104]

Answer:

a)

# for a g line, R = 1.211 μm

# for an I-line, R = 1.013 μm

b)

# for a g line, R = 0.726 μm

# for an I-line, R = 0.243 μm

c)

# for a g line, R = 0.605 μm

# for an I-line, R = 0.608 μm

Explanation:

We know that;

Rayleigh Resolution R = 0.5 × λ/NA

for a g line, λ = 436 nm

for an I-line λ = 365 nm

a)

Now when NA = 0.18

# for a g line, λ = 436 nm

R = 0.5 × 436/0.18 =  1.211 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.18 =  1.013 μm

b)

when NA = 0.30

# for a g line, λ = 436 nm

R = 0.5 × 436/0.30 =  0.726 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 =  0.243 μm

c)

when NA = 0.36

# for a g line, λ = 436 nm

R = 0.5 × 436/0.36 =  0.605 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 =  0.608 μm

6 0
3 years ago
What does a manufacturing engineer do?
Lisa [10]

Answer: Manufacturing engineers may be responsible for solving production problems, conducting cost-benefit assessments, or designing and manufacturing goods and systems using computer-aided design software. Plant engineers and process engineers are two terms used by professionals in this industry. Manufacturing engineers are in charge of new and existing production lines' technical management, maintenance, and development. Employers are looking for people that are commercially aware and have good technical and analytical skills. They are in charge of keeping production costs low while preserving the product or service's quality, and they have considerable project expertise and insight.

Explanation: See above.

I hope this helps.

6 0
3 years ago
Read 2 more answers
Other questions:
  • The moisture in hot, humid, stagnant air surrounding a cold-water pipeline continually diffuses to the cold surface where it con
    14·1 answer
  • A 2.599 g sample of a new organic material is combusted in a bomb calorimeter. The temperature of the calorimeter and its conten
    13·1 answer
  • A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted
    7·1 answer
  • What determines the depth of the foundation excavation
    9·2 answers
  • The convection heat transfer coefficient for a clothed person standing in moving air is expressed as h 5 14.8V0.69 for 0.15 , V
    12·2 answers
  • The following passage contains a fragment. Select the correct revision. Presley took the exuberance of gospel and added the freq
    7·1 answer
  • A long rod of 60-mm diameter and thermophysical properties rho=8000 kg/m^3, c=500J/kgK, and k=50 W/mK is initally at a uniform t
    8·1 answer
  • Effective presentations are: Have a central message Colorful and exciting Have many messages Are influence by a setting Created
    15·2 answers
  • 10 properties of metals?<br> ​
    10·2 answers
  • 5. A 15-nC point charge is at the origin in free space. Calculate V₁ if point P, is located at
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!