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viktelen [127]
3 years ago
8

Choose the best estimate. 589 - 473 = 150 100 50 200

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0
The answer is 100. I hope this helps!
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How do you find a vector of length 10 in the direction of v= <3,-2>?
Katena32 [7]
Hello,

We are going to used the theorem of Thalès.

||v||=√(3²+(-2)²)=√13

k*√13=10==>k=10/√13

w=k.v=10/√13<3,-2>

5 0
3 years ago
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Which set best describes the number(-16)?
algol13
-16 is a negative whole number.

Therefore, the <span>set of numbers that best describes -16 is the set of integers.</span>
8 0
3 years ago
91 rounded to the nearest hundred is 100 because 91 is closer to 100 than ? on the number line
Rufina [12.5K]

Answer:

yes

Step-by-step explanation:

91 is closer to 100 than 0

5 0
3 years ago
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Use the Quadratic Formula to solve the equation 4x^2−7=4x.
tino4ka555 [31]

Answer:

\large\boxed{x=\dfrac{1}{2}-\sqrt2\ or\ x=\dfrac{1}{2}+\sqrt2}

Step-by-step explanation:

\text{The quadratic formula of}\ ax^2+bx+c=0:\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{We have:}\\\\4x^2-7=4x\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\4x^2-4x-7=0\\\\a=4,\ b=-4,\ c=-7\\\\b^2-4ac=(-4)^2-4(4)(-7)=16+112=128\\\\\sqrt{b^2-4ac}=\sqrt{128}=\sqrt{64\cdot2}=\sqrt{64}\cdot\sqrt2=8\sqrt2\\\\x=\dfrac{-(-4)\pm8\sqrt2}{(2)(4)}=\dfrac{4\pm8\sqrt2}{8}\qquad\text{simplify by 4}\\\\x=\dfrac{1\pm2\sqrt2}{2}\to x=\dfrac{1}{2}\pm\sqrt2

6 0
3 years ago
Chloe notices that segment ST and segment VW are congruent in the image below.
IgorLugansk [536]
The SAS similarlity theorem is the type of similarlity that show that two triandles are similar by showing that two of the sides are similar with the angle between the two sides also similar.

Thus, given that <span>segment ST and segment VW are congruent, and also from the image it can be seen that angle S is congruent to angle V.

Thus, to show that </span>ΔSTU ≅ ΔVWX, we have to show that <span>US≅XV.

There</span>fore, the <span>step that could help her determine if ΔSTU ≅ ΔVWX by SAS is<span> US≅XV</span></span>
5 0
3 years ago
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