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VashaNatasha [74]
3 years ago
7

A stock has an expected return of 11.9 percent, its beta is .94, and the risk-free rate is 5.95 percent. What must the expected

return on the market be? (Do not round intermediate calculations and enter your answer as a percent rounded to 2 decimal places, e.g., 32.16.) Market expected return %
Business
1 answer:
bixtya [17]3 years ago
7 0

Answer:

The market expected return is 12.28%

Explanation:

According Miller and Modgliani Capital Asset Pricing Model,the expected return on a stock is given by the formula below:

Ke=Rf+Beta(Market expected return-Rf)

Rf is the risk free-rate of return

Ke=11.9%

Beta=0.94

risk-free rate of return=5.95%

11.9%=5.95%+0.94(MER-5.95%)

11.9%=5.95%+0.94MER-5.593 %

11.9%=0.357 %+0.94MER

11,9%-0.357%=0.94MER

11.543 %=0.94MER

MER=11.543%/0.94

MER=12.28%

The market expected rate having Miller and Modgiliani CAPM formula is 12.28%

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Since in the question it is mentioned that manager permit the assitant to make the decision but also scheduled the weekly meeting

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professionals who take onwership of their mistakes are said to have: A: a work ethic B: integrity C:dishonesty D:ingenuity
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Billy never lets money stay in his pockets, he thinks if it is there he has to spend it. Often he spends it on useless "stuff".
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You have borrowed $28,000 at an interest rate of 12% compounded annually. Equal payments will be made over a four-year period, w
Sloan [31]

Answer:

A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]

A = 28000 [\frac{0.12*1.574}{1.574-1}]

A=28000*0.3292 = 9218.564

So then the annual pay would be $ 9218.564 for this case

Explanation:

For this question we can use the Equivalent annual value (A) given by the following expression:

A = PV [\frac{i (1+i)^t}{(1+i)^t -1}]

Where PV = 28000 represent the pesent value

i = 0.12 since the rate is yearly

t = 4 since we have 4 years to pay

So then we have everything to replace and we got:

A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]

A = 28000 [\frac{0.12*1.574}{1.574-1}]

A=28000*0.3292 = 9218.564

So then the annual pay would be $ 9218.564 for this case

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kari74 [83]
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