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3 years ago

Alexander is measuring the width of objects. The smallest measurement his ruler displays is centimeters. Rather than

Chemistry

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

There can be error in millimetres.

Explanation:

The rounding off can create errors in exact measurement. There can be errors in the measured value and actual measurement of the object. Alexander has rounded his calculation to nearest centimetre then it is possible he can make errors in millimetre calculations. The measured width of the object will not be the actual measurement and it might differ slightly.

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Can someone explain this to me, please?

zimovet [89]

Answer:

Isotopes have same atomic numbers, no. of protons and no. of electrons. Only their no. of neutrons and atomic mass are changed.

Atomic Mass = 24

Atomic No. = 11

Hence,

No. of protons in Na-24 = 11

No. of neutrons = Atomic Mass - Atomic Number

No. of neutrons = 24 - 11

No. of neutrons = 13

Atomic Number = 11

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

5 0

3 years ago

Is silicon a compound yes or no

Crazy boy [7]

Answer: Yes

Explanation: Silicon is never found as a free element naturally, meaning it always occurs with other elements.

4 0

3 years ago

Read the passage below and choose the best answer for the main idea of the passage:

Crank

Answer: C

Explanation:

4 0

3 years ago

Write a balanced nuclear equation for the formation of 28 Si 14 from beta-minus emission.

Fantom [35]

Answer:

Phosphorus-28 undergoes beta-minus decay to produce

an electron,
a Silicon-28 nuclei, and
an electron antineutrino.

$\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}$

Explanation:

In simple words, when a nucleus undergoes beta-minus decay, a neutron is converted to a proton. An electron and an electron antineutrino will be released.

$\rm ^{1}_{0}n^{0} \to ^{1}_{1}p^{+} + ^{\phantom{-}0}_{-1}e^{-} + \bar{\mathnormal{v}}_{\rm e}$ .

One way to tell whether a neutron is converted to a proton, but not vice versa, is to check the sum charges on the two sides of this equation.

Left-hand side: 0. Neutron is neutral.
Right-hand side: 1 + (-1) = 0. Each proton carries a charge of +1. Each electron (beta-minus particle) carries a charge of -1. Antineutrinos are neutral.

The charges on the two sides of this equation is the same. Hence this nuclear equation is possible (but not necessarily correct; however, if the proton and the neutron are in the wrong place the charge won't even be the same.)

Since the mass number of a proton and a neutron are both 1, the overall mass number of the atom will stay the same.

The atomic number is the number of protons in each atom. That number determines the symbol and the chemical properties of the atom. When one neutron in an atom is converted to a proton, the atomic number of the atom will increase by 1.

The atomic number of the daughter nucleus, silicon, is 14. It takes a parent nucleus with atomic number $14 - 1 = 13$ to produce a silicon atom. Refer to a modern periodic table. Atomic number $13$ corresponds to the element aluminum.

Also, the mass number of the daughter nucleus is 28. Since the mass number would stay the same in a beta decay, the mass number of the parent nucleus would also be 28. In other words, it takes an aluminum-28 atom to undergo beta-decay to produce a silicon-28 atom.

Complete the other details (electron and electron antineutrino) to obtain the equation

$\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}$ .

6 0

3 years ago

If I want to accelerate a mass of 3 kg at 5 m/s2 then how much force should I apply?

Stolb23 [73]

<u>Answer:</u> The force that must be applied is 15 N.

<u>Explanation:</u>

Force exerted on the object is defined as the product of mass of the object and the acceleration of the object.

Mathematically,

$F=m\times a$

where,

F = force exerted = ?

m = mass of the object = 3 kg

a = acceleration of the object = $5m/s^2$

Putting values in above equation, we get:

$F=3kg\times 5m/s^2=15N$

Hence, the force that must be applied is 15 N.

5 0

3 years ago