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user100 [1]
3 years ago
14

Alexander is measuring the width of objects. The smallest measurement his ruler displays is centimeters. Rather than

Chemistry
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

There can be error in millimetres.

Explanation:

The rounding off can create errors in exact measurement. There can be errors in the measured value and actual measurement of the object. Alexander has rounded his calculation to nearest centimetre then it is possible he can make errors in millimetre calculations. The measured width of the object will not be the actual measurement and it might differ slightly.

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Calculate the molarity of 90.0 mL of a solution that is 0.92 % by mass NaCl. Assume the density of the solution is the same as p
jeka94
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
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m(solution) = V(solution) · d(solution).
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8 0
3 years ago
What is one way to make a positive impact on air quality to reduce air pollution​
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using public transportation

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5 0
3 years ago
The (15-35-15) number on a bag of fertilizer is calculated by an outdated method. All modern fertilizers use PO43- as a source o
Alik [6]

The (15-35-15) number on a bag of fertilizer is calculated by an outdated method.  Using the knowledge of the old methods, the number of moles of phosphorus found in 10.0 grams of phosphorus is 0.05 mole.

The (15-35-15) number on the bag of fertilizer is used for:

  • Nitrogen 15 : Phosphorus pentoxide 35: potassium oxide 15

Thus, in a 100-gram bag of fertilizer, there are 35 grams of phosphorus pentoxide P₂O₅.

∴

To determine the number of moles of 10 grams of phosphorus pentoxide in (15-35-15) bag of fertilizer, we have:

\mathbf{=10 \times \dfrac{35}{100} \  grams \ of \ P_2O_5}

= 3.5 grams of P₂O₅

Recall that:

\mathbf{Number of moles = \dfrac{mass}{molar \ mass}}

  • the molar mass of P₂O₅ = 142 g/mol

∴

\mathbf{Number of moles = \dfrac{3.5\  g}{ 142 \ g/mol}}

\mathbf{Number of moles = 0.0246 \ mol}

Provided that 1 mole of P₂O₅ harbors 2 moles of phosphorus;

Then;

The number of phosphorus present in 10.0 grams of (15-35-15) fertilizer is:

= 0.0246 moles × 2

= 0.0492 moles

≅ 0.05 moles

Therefore, we can conclude that the number of moles of phosphorus found in 10.0 grams of  (15-35-15) bag of fertilizer is 0.05 moles.

Learn more about phosphorus here:

brainly.com/question/4622631?referrer=searchResults

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