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Thepotemich [5.8K]

3 years ago

15

When heat energy is added, two changes are observed: change A: solid changes to a liquid. Change B: Solid changes directly to a

gas. What are the names for phase changes A and B

1 answer:

sammy [17]3 years ago

7 0

Answer:

the answer is solid change into liquide.

please mark me as a brainlist..

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The partial pressure of N2 in a mixture of gases, where the total pressure is 1.50 atm, is 300. torr. What is the mole fraction

makvit [3.9K]

Answer:

The mole fraction of N₂ is 0.26.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

PA = XA * PT

In this case:

PA= PN₂= 300 torr
XA=XN₂= ?
PT= 1.50 atm= 1140 torr (being 1 atm= 760 torr)

Replacing:

300 torr= XN₂*1140 torr

Solving:

$X_{N_{2} } =\frac{300 torr}{1140 torr}$

XN₂= 0.26

<u><em>The mole fraction of N₂ is 0.26.</em></u>

6 0

2 years ago

A 2.4 L balloon holds 3.7 mol He. If 1.6 mol He are added to the balloon, what is the new volume?

Elanso [62]

For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
$\frac{V}{n} = k$
where V-volume, n-number of moles and k - constant
Therefore at 2 instances
$\frac{V1}{n1} = \frac{V2}{n2}$
where V1 and n1 are for 1st instance
and V2 and n2 are for 2nd instance
therefore
$\frac{V1}{n1} = \frac{V2}{n2}$
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated $\frac{2.4}{3.7} = \frac{V2}{5.3}$
V2 = 2.4 x 5.3 / 3.7
= 3.4 L
Answer is 1st option 3.4 L

6 0

3 years ago

Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}$

Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

The equilibrium partial pressure of $N_2$ = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of $N_2$ is 7.8 atm.

3 0

3 years ago

How much power is used if a force of 54 newtons is used to pull a wagon a distance of 10 meters in 6 seconds? 3,240 W 90 W 32.4

timama [110]

Power is defined in a mathematical expression as P = F x v where F is in N and v is in m/s. From the given equation, the v = d/t which is v = 10/ 6, then substituting the answer to the power formula W = 54 N (10/6 m/s) = 90 Watts.

3 0

3 years ago

Read 2 more answers

Which of the following is an example of anaerobic respiration?

Andrews [41]

Respiring while swimming underwater
Because anaerobic respiration means respiration with no oxygen, and there is no oxygen underwater

8 0

3 years ago