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scoray [572]
3 years ago
15

Which is an example of a highly unstable isotope that is often used in fission reactions?

Chemistry
2 answers:
GuDViN [60]3 years ago
4 0
The right answer to this question is U-235. It is an isotope of Uranium and it is an unsteady heavy metal used in fission reactions because it can run long chains of reactions. I hope this helps.
Marta_Voda [28]3 years ago
4 0

Answer:

C. U-235

Explanation:

A fission reaction is one in which an unstable radioisotope breaks down into smaller nuclei when bombarded with energetic particles.

The highly unstable isotope that is often used in fission reactions is U-235. When bombarded with neutrons that atom breaks down to form krypton and barium along with the release of a large amount of energy. The reaction is given as:

₉₂U²³⁵ +  ₀n¹  →   ₃₆Kr⁸⁹  +  ₅₆Ba¹⁴⁴  + 3₀n¹ + 210 Mev energy

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Name a device or other object whose major purpose is to convert
Alenkinab [10]

Answer:

Storage battery oe cell

Explanation:

The storage battery or cell is a device that coverts chemical energy into light energy when required.

During charging of battery, there is some chemical changes in the battery and absorb energy. The absorbed energy is converted into electrical energy when connected to an external load.

Hence, the correct answer is "Storage battery or cell".

4 0
3 years ago
An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?
matrenka [14]

Answer:

In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.

Explanation:

C1×N1 = C2×N2

If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.

Balancing the two,

3 × A = -2 × B

To be equal, A = 2 and B = 3

Therefore, A²B³

6 0
2 years ago
What is defined as the number of atoms surrounding an atom in a crystal lattice?
Simora [160]

Answer:

coordination number

Explanation:

Coordination number -

In a crystal lattice , the number of atoms that are surrounded to a particular atom , is referred to as the coordination number of the crystal.

In the field of crystallography and chemistry , it is also called the ligancy.

In coordination chemistry , the number of ligands attached to the central metal atom is also known as the coordination number of the coordination compound.

Hence, from the given statement of the question,

The correct term is coordination number.

4 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
3 years ago
Disadvantages of Mendeleev's periodic table​
mestny [16]

Answer:

Various limitations of Mendeleev's periodic table are:-

Position of hydrogen - he couldn't assign a correct position to hydrogen as it showed properties of both alkali and halogens .

Position of isotopes - he considered that the properties of elements are a function of their atomic masses. Hence isotopes of a same element couldn't be placed.

In the d-block , elements with lower atomic number were placed before higher atomic number.

Explanation:

3 0
3 years ago
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