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sattari [20]
2 years ago
15

Help pleaseeeeeeeee with this question

Chemistry
2 answers:
Bumek [7]2 years ago
8 0
Maybe glass not too sure
Shtirlitz [24]2 years ago
8 0

Answer:

(C) Vacuum

Explanation:

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Why can liquid water never go over the boiling point temperature? Where is the energy (heat) that is being added going?
Afina-wow [57]

it's turned into steam.

It dissolves and turns into steam no explanation needed,it'sa simple answer,idk who reported it but i'll answer it again:)

7 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac
Tanya [424]

Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

Explanation:

we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

Thus:

K1 = K^6 * Ky

4 0
2 years ago
How do the differences in the polyatomic ions po3 3- and po4 3- help you determine whether each ends in -ite or -ate?
Tcecarenko [31]

There is a rule in naming polyatomic anions containing oxygen. Those names ending in <em>–ate</em> are given to the most common oxyanion of an element. While those names ending in <em>–ite</em> are for those that contains fewer O atom for the same charge. Since PPO_{3} ^{3-} has fewer O atoms, its name ends in <em>–ite</em>. Thus, PPO_{3} ^{3-}  is phosphite while PPO_{4} ^{3-}  is phosphate.

4 0
3 years ago
Write a letter to your friend describing your feelings after you left the school
fredd [130]
Dear friend,
How are you doing? I finally switched to my new school and it's been so hard adjusting. But I know I have a new chance at making new friends and memories. Also, I can learn new things, like interacting with new people and how to keep my anxiety low. I really miss us hanging out and how much we'd laugh and get in trouble at class. But i really hope to see you soon & that it hasn't gone terribly wrong for you since i left.
your friend,
name
8 0
2 years ago
1. If I have 45 L of He in a balloon at 25 degrees celsius and increase the temperature of the
Greeley [361]

Use Charles' Law: V1/T1 = V2/T2. We assume the pressure and mass of the helium is constant. The units for temperature must be in Kelvin to use this equation (x °C = x + 273.15 K).

We want to solve for the new volume after the temperature is increased from 25 °C (298.15 K) to 55 °C (328.15 K). Since the volume and temperature of a gas at a constant pressure are directly proportional to each other, we should expect the new volume of the balloon to be greater than the initial 45 L.

Rearranging Charles' Law to solve for V2, we get V2 = V1T2/T1.  

(45 L)(328.15 K)/(298.15 K) = 49.5 ≈ 50 L (if we're considering sig figs).

7 0
2 years ago
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