The correct answer is C
(X-5)²+(Y-7)²=50
Answer:
option A
Step-by-step explanation:
Since All values in confidence interval are less than 3.12, we do not have sufficient evidence
as degree of freedom is sample size -1 ; hence df =20-1 =19
In construction of the confidence interval, a t-value with 19 degrees of freedom was used therefore option b, c and d are incorrect
also, In construction of the confidence interval, a z-value with 10 degrees of freedom was used
The interquartile range for Group A employees is 1 more than the interquartile range for Group B students.
