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Yanka [14]
3 years ago
11

How do i write an equation in point-slope form for a horizontal line that passes through(4, –2)??

Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

y = -2

Step-by-step explanation:

Given

Horizontal Line

(x_1,y_1) = (4,-2)

Required

Determine the equation

The equation is calculated using:

y - y_1 =m(x-x_1)

Where

m = slope

Because the line is a horizontal line, then:

m = 0

Substitute 0 for m and values for x1 and y1 in y - y_1 =m(x-x_1)

y - (-2) = 0(x -4)

y +2 = 0(x -4)

y +2 = 0

Subtract 2 from both sides

y +2-2 = 0-2

y = -2

Hence, the equation is: y = -2

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A ball is launched out of a cannon that is 24 feet off the ground. The height of the ball after "t" seconds is represented by
Olegator [25]

Given:

The height of ball is represented by the below function:

h(t)=-16t^2+20t+24

To find:

The number of seconds it will take to reach the ground.

Solution:

We have,

h(t)=-16t^2+20t+24

At ground level, the height of ball is 0, i.e., h(t)=0.

-16t^2+20t+24=0

Taking out greatest common factor.

-4(4t^2-5t-6)=0

4t^2-5t-6=0

Splitting the middle term, we get

4t^2-8t+3t-6=0

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t=2 and t=-\dfrac{3}{4}

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Therefore, the ball will reach the ground after 2 seconds.

7 0
3 years ago
Please help asap 20 pts
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Bumek [7]

Answer:

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Step-by-step explanation:

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3 years ago
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AURORKA [14]

Hey there!!

Given equation :

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