Victoria bought a jacket in the sale which had 20% off. If it cost ?36 on sale what did it cost before the sale?

Mathematics

1 answer:

Basile [38]2 years ago

7 0

Answer:

The jacket costs $45

Step-by-step explanation:

In order to find this, notice that the price of the sale represents 80% of the total cost. This is because we took 20% away with the sale. Now we can find the overall amount by dividing the sale cost by the amount it represents.

$36 / 80% = $45

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Find four consecutive integers whose sum is 114.

Nezavi [6.7K]

If n is the first of these integers, then the other three are n + 1, n + 2, and n + 3. Then

n + (n + 1) + (n + 2) + (n + 3) = 114

4n + 6 = 114

4n = 108

n = 27

So the four numbers are 27, 28, 29, and 30.

6 0

2 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

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In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

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✰ Given Information :-

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Hypotenuse = 22 ft.
Base = 10 ft.

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✰ To Find :-

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The value of side or the perpendicular

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✰ Formula Used :-

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$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

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✰ Solution :-

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$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$