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iragen [17]
3 years ago
11

Victoria bought a jacket in the sale which had 20% off. If it cost ?36 on sale what did it cost before the sale?

Mathematics
1 answer:
Basile [38]3 years ago
7 0

Answer:

The jacket costs $45

Step-by-step explanation:

In order to find this, notice that the price of the sale represents 80% of the total cost. This is because we took 20% away with the sale. Now we can find the overall amount by dividing the sale cost by the amount it represents.

$36 / 80% = $45

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Answer:

5.5 or 5 1/2

Step-by-step explanation:

44 students ÷ 8 rows = 5.5

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Answer:

The parent sine graph y=sin(x) has a range of -1 ≤ y ≤ 1

It crosses the x-axis x = 0° ± 180°n

The maximum points occur when x = 90° ± 360°n and y = 1

The minimum points occur when x = 270° ± 360°n and y = -1

The sketch the graph of function y=sin(x)+2 we simply move the graph of y=sin(x) up 2 units.

So this means it will have a range of 1 ≤ y ≤ 3

It no longer crosses the x-axis.

The maximum points occur when x = 90° ± 360°n and y = 3

The minimum points occur when x = 270° ± 360°n and y = 1

<u>Attached diagram</u>

The parent function y=sin(x) is shown in grey (dashed line)

The function y=sin(x)+2 is shown in red.

4 0
2 years ago
These two trapezoids are similar What is the correct way to complete the similarity statement?
pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

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To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

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