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Andreyy89
3 years ago
14

What is the IQR of 3,7,8,11,13,15,16

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
5 0

The IQR = Q3 - Q1

In your set, Q3 = 15, Q1 = 7

Therefore, 15 - 7 = 8

The IQR is 8.

Ann [662]3 years ago
3 0

Answer:

8

Step-by-step explanation:

3, 7, 8, 11, 13, 15, 16

Median: 11

lower quartile: 7

upper quartile: 15

interquartile range: 15 - 7 = 8

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Could someone explain how to do this, I have no idea how...
alexira [117]

Answer:

2a²

Step-by-step explanation:

Pair 'like' terms with 'like' terms, ie numbers go with numbers, and 'a's go with 'a's.

Lets deal with the top of the fraction first:

4ax3a³

Rearrange it so you have numbers beside numbers and 'a's beside 'a's:

(4x3)x(axa³)

12x(a⁴) <em>(because nᵃxnᵇ=nᵃ⁺ᵇ)</em>

12a⁴

Now, instead of (4ax3a³)/6a², we have 12a⁴/6a²

First divide the numbers: 12/6 =2

Now divide the 'a' parts: a⁴/a²=a² <em>(because nᵃ/nᵇ=nᵃ⁻ᵇ)</em>

Now we have 2a²

7 0
3 years ago
Pleaseeee help meee☹️
VashaNatasha [74]
The answer is two :))))
7 0
3 years ago
Read 2 more answers
30 Points please help!! Please explain too!
sergiy2304 [10]
Initial: 200 feet = opp. side
Angle = 17.31, adj. Side = a
So tan (17.31) = opp. Side / adj. Side
tan (17.31) = 200 / a
--> a = 200/tan17.31 = 641.73
When stopped: adj. Still = a
Opp. Side still = 200, angle = 46.41
tan46.41 = 200 / a
--> a = 200/tan46.41 = 190.39
Now subtract those two distances to get the distance traveled from initial to when it stopped:
641.73 - 190.39 = 451.34 feet
3 0
3 years ago
3y-4=6- 2y<br> y=?<br> solve pleaseeeeeeeeeee
dybincka [34]
Y= 2 is the answer
Hope this helps
4 0
3 years ago
Read 2 more answers
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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