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3 years ago

The waverly company issued 4,000 shares of common stock worth 200,000.00 total. What is the par value of each share?

Mathematics

1 answer:

yuradex [85]3 years ago

3 0

The value per share is 50 per share.

In order to find this, you take the total value of the stock and then divide by the number of shares.

200,000/4,000 = 50.

Therefore, it is 50 per share.

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List 5 fractions that are between 1/3 and 4/5

koban [17]

9514 1404 393

Answer:

2/5, 7/15, 8/15, 3/5, 2/3

Step-by-step explanation:

If these fractions are expressed with a common denominator, that would be 3×5 = 15. Then the given fractions are 1/3 = 5/15, and 4/5 = 12/15. The numerators 5 and 12 differ by 7, so we can easily choose 5 fractions in that range:

6/15 = 2/5

7/15

8/15

9/15 = 3/5

10/15 = 2/3

_____

Alternate solutions

There is no requirement for the fractions to be written any particular way or with any particular spacing. The limits in decimal are 1/3 = 0.3333...(repeating) and 4/5 = 0.8. We could choose the decimal fractions ...

0.34, 0.40, 0.50, 0.60, 0.70

0.41, 0.52, 0.63, 0.74, 0.79

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3 years ago

This box can be packed with 48 unit cubes

AURORKA [14]

Answer:

Please clarify the question so I can answer :)

Step-by-step explanation:

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3 years ago

Find the difference between 7/10 and 14/15

miskamm [114]

Answer:

7/30

Step-by-step explanation:

The difference means subtracting so 14/15 - 7/10 = 7/30 or decimal form is 0.23

7 0

3 years ago

Can someone help me do this

DiKsa [7]

The answer is Angle T = angle N

8 0

3 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

Binomial Series

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

Factorial is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

$\implies \left(\dfrac{120}{6}\right)a^{3}b^3$

$\implies 20a^3b^3$

7 0

2 years ago